Answer:
a. $60
Step-by-step explanation:
We will use simple interest formula to solve our given problem.
, where
A= Amount after t years.
P= Principal amount.
r= Interest rate in decimal form.
t= Time in years.
Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.
As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.
12 months = 1 year.
Now let us find amount repayable after 12 months for borrowing $1000.
Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.
Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.
Now let us find difference between both repayable loan amounts.
Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.
Answer:
If you are <u>traversing squares</u> then 7 different paths can be taken
If you are <u>traversing edges </u> then 36 different paths can be taken
Step-by-step explanation:
I have attached a picture that would describe the grid which is 7 units long.
The solution to the general problem is if you have to take X right steps, and Y down steps then the number of routes is simply the ways of choosing where to take the down (or right) steps. Such that:
Basically its the combination of terms.
In this problem,
If you are <u>traversing squares</u> then there are 6 right steps and 1 down step,
7 C 1 = 7 C 6= 7
If you are <u>traversing edges </u> then there are 7 right steps and 2 down steps:
9 C 2 = 9 C 7= 36
Answer:
The graph that best fits this model of profit and price per unit is attached to this solution.
Step-by-step explanation:
A couple of graphs are missing from the question. According to the full question as obtained online, there are a number of graph options, and we are expected to pick the best option. I would not add all the other graphs to limit the chances of deletion due to violating community guidelines.
The function is to model the profits of a new pet-monitoring system, so, if the profits are y and x is the price per unit, y = f(x)
The profits vary as the price per unit varies, there is no profit made until the price reaches
$95 per unit, a maximum profit at a price of $140 per unit, and no profit at a price over $185 per unit.
This description of the curve shows that y is negative at values of x less than $95, then the profits increase when x varies between $95 and $140. The profits reach a maximum at $140 and then the profits start to decline as x increases again, the profits go to 0 at x = $185.
This description shows that the function is a quadratic function with a graph that is n-shaped, peaking at x=185 and the graph crosses the x-axis at x=95 and x=185.
The most fitting graph for this model is attached to this solution provided.
From the graph, all the descriptions above are evident.
Hope this Helps!!!
