Formula of hydrated sodium carbonate : Na₂CO₃.10H₂O, so moles of water in one mole of hydrated salt = 10
<h3>Further explanation</h3>
Hydrate is a compound that binds water (H₂O), usually in the form of crystals/ solids
If these compounds are dissolved in water or heated, the hydrates can decompose:
Example: X.YH₂O (s) → X (aq) + YH₂O (l)
The formula for the hydrated compound contains: YH2O
The mole ratio shows the ratio of the coefficients of the hydrate compound
10.45 hydrated sodium carbonate(Na₂CO₃.xH₂O) were heated until 3.87 of 3.87of anhydrous (Na₂CO₃) remained, so
mass H₂O released :
mass Na₂CO₃ = 3.87 g
mol ratio Na₂CO₃(MW= g/mol) : H₂O(MW=18 g/mol) =
Answer:
Solubility indicates the maximum amount of a substance that can be dissolved in a solvent at a given temperature. Such a solution is called saturated,it is calculated by dividing the mass of the compound by mass of the solvent then multiply by the molar concentration.
molar mass of solvent (Agl)= 107.8682 + 126.90447 = 234.77267g/mol
For 0.038M of Nal
molar mass of Nal compound= 22.99 + 126.90447 = 149.89447g/mol
solubility = [ 149.89447 / 234.77267] * 0.038 = 0.024
For 0.05M of AgNO3
molar mass of AgNO3 compound = 107.8682 + 14.01 + 3(16) = 169.8782g/mol
solubility = [169.8782 / 234.77267] * 0.05 = 0.036
For 0.025M of KI
molar mass of KI compound = 39.0983 + 253.8089 = 292.9072g/mol
solublity = [292.9072 / 234.77267] * 0.025 = 0.031
For 0.0125M of Lil
molar mass of Lil compound = 6.941 + 253.8089 = 260.7499g/mol
solubility = [260.7499 / 234.77267] * 0.0125 = 0.014
Therefore the solution with the highest solubility is 0.05M of AgNO3
Answer: The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.
Explanation:
Energy required to produce free chlorine atoms from one mole of chlorine gas :
= 242.8kJ = 
(1kJ=1000J)
1 mole = 
molecules
For molecules = 242,800 Joules
For one molecule of chlorine gas = 
According to photoelectric equation:
E = Energy of the photon of light used to produce free chlorine atoms
= frequency of the light used to produce free chlorine atoms
h = Planck's constant =
, c = speed of light=
= wavelength of the light used to produce free chlorine atoms
The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.
<u>Answer:</u> The particle released in the given reaction is one alpha particle
<u>Explanation:</u>
In a nuclear reaction, the total mass and total atomic number remains the same.
For the given fission reaction:
Total mass on reactant side = total mass on product side
222 = A + 218
A = 4
Total atomic number on reactant side = total atomic number on product side
86 = Z + 84
Z = 2
The isotopic symbol of unknown element is 
. Another name of helium atom is alpha particle.
Hence, the particle released in the given reaction is one alpha particle
Hello!
To find the amount of atoms that are in 80.45 grams of magnesium, we will need to know Avogadro's number and the mass of one mole of magnesium.
Avogadro's number is 6.02 x 10^23 atoms, and one mole of magnesium is equal to 24.31 grams.
1. Divide by one mole of magnesium
80.45 / 24.31 = 3.309 moles (rounded to the number of sigfigs)
2. Multiply moles by Avogadro's number
3.309 x (6.02 x 10^23) = 1.99 x 10^24 (rounded to the number of sigfigs)
Therefore, there are 1.99 x 10^24 atoms in 80.45 grams of magnesium.
