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2 years ago

You open a can of soda at room temperature and hear a hiss. What factor has changed inside container

Chemistry

2 answers:

zzz [600]2 years ago

7 0

Answer:

pressure of gas

Explanation:

The pressure is decreasing due to the release of gas. Less molecules = lower pressure.

klio [65]2 years ago

6 0

The soda has been exposed to oxygen. Therefore, a chemical reaction is taking place.

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Imagine that a new polyatomic anion called "platoate" is invented. What would an acid of "platoate" be named?

o-na [289]

<h3>Answer:</h3>

Platoic Acid

<h3>Explanation:</h3>

While naming Carboxylic Acids we know that when the Carboxylic Acid looses proton it is converted into corresponding conjugate base called as Carboxylate.

Examples:

HCOOH → HCOO⁻ + H⁺

Formic acid Formate Ion

H₃CCOOH → H₃CCOO⁻ + H⁺

Acetic acid Acetate Ion

H₅C₂COOH → H₅C₂COO⁻ + H⁺

Propanoic acid Propanoate Ion

Therefore, if the conjugate base is Platoate then the corresponding acid will be Platoic Acid means we will replace the -ate by -ic acid i.e.

RCOO⁻ + H⁺ → RCOOH

Platoate Ion Platoic Acid

8 0

2 years ago

Read 2 more answers

BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w

Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

Explanation:

Given: The base dissociation constant: $K_{b}$ = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: $K_{w}$ = 1 × 10⁻¹⁴

The acid dissociation constant ( $K_{a}$ ) for the weak acid (BH⁺) can be calculated by the equation:

$K_{a}. K_{b} = K_{w}$

$\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}$

$\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}$

Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:

Reaction involved: BH⁺ + H₂O ⇌ B + H₃O+

Initial: 0.1 M x x

Change: -x +x +x

Equilibrium: 0.1 - x x x

The acid dissociation constant: $K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}$

$\Rightarrow K_{a} = \frac{x^{2}}{0.1 - x}$

$\Rightarrow 1\times 10^{-10} = \frac{x^{2}}{0.1 - x}$

$As, x$

$\Rightarrow 0.1 - x = 0.1$

$\therefore 1\times 10^{-10} = \frac{x^{2}}{0.1 }$

$\Rightarrow x^{2} = (1\times 10^{-10})\times 0.1 = 1\times 10^{-11}$

$\Rightarrow x = \sqrt{1\times 10^{-11}} = 3.16 \times 10^{-6}$

Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M

Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44

Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

5 0

2 years ago

What is the percentage of water in the following compound? Answer using three significant figures. Sodium carbonate decahydrate,

Karo-lina-s [1.5K]

The trick for this problem is to understand atomic mass: the fact that different atoms have different masses. What we need to do is add up all the atomic masses of the compound and work out the ratio of mass of water to the mass of sodium carbonate. Atomic masses are often given for each atom in the periodic table, but you can look them up on google too.

You can do this by adding up individual atoms for each molecule, or you can shortcut and lookup the molar mass of the compound (i.e.the task already done for you).

The molar mass of water is 18.01g/mole so for 10 moles of water we have a mass of 180.1g.

The molar mass of sodium carbonate is 106g/mole (google).

So the total mass of the sodium carbonate decahydrate compound is 180.1+106 = 286.1g, of which water would make up 180.1g, so the percentage of water is is 180.1/286.1 = 0.629, so we can round this to 63%

:)

3 0

2 years ago

Read 2 more answers

A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calc

GrogVix [38]

Answer:

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is $(\frac {J}{Kg.K})$

C = Q/m. ∆T

C – Specific heat $(\frac {J}{Kg.K})$ 

Q- heat energy (J)

M – Mass (Kg)

∆T- change in temperature (K) 

Explanation:

Given data:

M= 140 g = 0.14 Kg

Q – 1080 Joules.

∆T – 98.4 – 62.2 = 36.2

Substituting the given data in Equation

Specific heat of Aluminium = $\frac {1080}{(0.14 \times 36.2)} = 213.10 (\frac {J}{Kg.K})$

3 0

2 years ago

Read 2 more answers

which diagram best illustrates the ion-molecule attractions that occur when the ions of NaCl(s) are added to water

tatuchka [14]

Diagram is on the picture below.
Answer is: 1).
Sodium chloride is ionic compound and in the water dissociate in sodium cation (positive charge) and chloride anion (negative charge). Water is polar compound, oxagan has negative charge and hydrogen charge. Positive interact witn negative charge and negative with positive charge.

8 0

2 years ago