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PSYCHO15rus [73]
1 year ago
5

Which process contributes to the formation of layers in protoplanets when unstable elements release particles and energy?

Chemistry
2 answers:
Korolek [52]1 year ago
8 0

Answer:

radioactive decay

Explanation:

i just took the guiz and got it right

sertanlavr [38]1 year ago
5 0

Answer:

c

Explanation:

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Which liquid materials have strong odor and weak odor?
densk [106]

<span>Odor refers to the fragrance caused by one or more volatilized chemical compounds. It can be strong or weak. </span>
Strong odor have: Sodium Hypochlorite, <span>Muriatic Acid, Sulphuric Acid, Ammunlom Sulfide. </span> Butyl ,Butyric Acid, Pyridine 

<span>Weak Odors have </span><span>Spray Glue, Dry Erase Markers, Paint cleaners.</span><span> Water.</span>

5 0
2 years ago
Use enthalpies of formation given in appendix c to calculate δh for the reaction br2(g)→2br(g), and use this value to estimate t
Contact [7]

Given reaction represents dissociation of bromine gas to form bromine atoms

Br2(g) ↔ 2Br(g)

The enthalpy of the above reaction is given as:

ΔH = ∑n(products)ΔH^{0}f(products) - ∑n(reactants)ΔH^{0}f(reactants)

where n = number of moles

ΔH^{0}f= enthalpy of formation

ΔH = [2*ΔH(Br(g)) - ΔH(Br2(g))] = 2*111.9 - 30.9 = 192.9 kJ/mol

Thus, enthalpy of dissociation is the bond energy of Br-Br = 192.9 kJ/mol

3 0
2 years ago
If 4.9 kg of CO2 are produced during a combustion reaction, how many molecules of CO2 would be produced?
solmaris [256]

Answer:

6.7 x 10²⁶molecules

Explanation:

Given parameters

Mass of CO₂  = 4.9kg  = 4900g

Unknown:

Number of molecules  = ?

Solution:

To find the number of molecules, we need to find the number of moles first.

 Number of moles  = \frac{mass}{molar mass}

          Molar mass of CO₂  = 12 + 2(16)  = 44g/mol

   Number of moles  = \frac{4900}{44}  = 111.36mole

A mole of substance is the quantity of substance that contains the avogadro's number of particles.

       1 mole  = 6.02 x 10²³molecules

     111.36 moles  =   111.36 x 6.02 x 10²³molecules   = 6.7 x 10²⁶molecules

5 0
2 years ago
Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, 0.5^{n}

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

8 0
2 years ago
Read 2 more answers
Which statement below correctly identifies the number of subatomic particles inside and outside the nucleus of an argon atom?
Juliette [100K]

Answer:

A

Explanation:

6 0
2 years ago
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