Answer:
0.1 is the retention factor.
Explanation:
Distance covered by solvent ,
Distance covered by solute or ion,
Retention factor
is defined as ratio of distance traveled by solute to the distance traveled by solvent.
0.1 is the retention factor.
Answer:
The average persons requires 75000 breaths to exhale 1.0 Kg of fat
Explanation:
Note: The question is incomplete. The complete question is given below:
"The human body burns glucose (C6H1206) for energy according to this chemical reaction:
C6H1206 + 602----> 6CO2 + 6H20
The products of the reaction are carbon dioxide (CO2) and water (H20). Interestingly, all of the carbon dioxide and much of the water exits the body through the lungs: on every breath, the average person exhales 500 mL of air, which is typically enriched to 4% CO2 and 5% water vapor by volume. In short, when a person loses weight by dieting, the weight that is lost actually departs his body as a gas, every time he exhales. Each kilogram of body fat lost requires exhaling about 3.0 kg of carbon dioxide. Calculate how many breaths it takes an average person to "exhale" 1.00 kg of fat. Round your answer to the nearest thousand. You'll need to know that the density of CO2 is 2.0 kg/m³”.
Volume of air exhaled on average per breath = 500 mL
Volume of CO2 exhaled per breath = 4/100 × 500 = 20 mL
Since, 1000000 mL = 1 m³;
20 mL = 0.00002 m³
3.0 kg of CO2 is exhaled per Kg of fat.
Density of CO2 = 2.0 Kg/m³
Volume = mass/density
Volume of 3.0 Kg CO2 = 3.0/2.0 = 1.5 m³
Number of breaths that will have a volume of 1.5 m³ = 1.5/0.00002 = 75000 breaths.
Answer : The energy released is -3319.7 KJ.
Solution : Given,
Mass of methane = 59.7 g
Molar mass of methane = 16 g/mole
The value of 
is in negative that means the energy is releasing.
First we have to calculate the moles of methane.
Moles of methane = 
Now we have to calculate the amount of energy released.
The given reaction is,
From the reaction, we conclude that
1 mole of methane releases -890 KJ/mole of energy
3.73 moles of methane releases 
of energy
Therefore, the energy released is -3319.7 KJ.
Answer:
The energy released in the decay process = 18.63 keV
Explanation:
To solve this question, we have to calculate the binding energy of each isotope and then take the difference.
The mass of Tritium = 3.016049 amu.
So,the binding energy of Tritium = 3.016049 *931.494 MeV
= 2809.43155 MeV.
The mass of Helium 3 = 3.016029 amu.
So, the binding energy of Helium 3 = 3.016029 * 931.494 MeV
= 2809.41292 MeV.
The difference between the binding energy of Tritium and the binding energy of Helium is: 32809.43155 - 2809.412 = 0.01863 MeV
1 MeV = 1000keV.
Thus, 0.01863 MeV = 0.01863*1000keV = 18.63 keV.
So, the energy released in the decay process = 18.63 keV.
Answer:
See explanation
Explanation:
Sr(s) + 2HCl(aq) -----> SrCl2(aq) + H2(g)
Ionically;
Sr(s) + 2Cl^-(aq) ----> SrCl2(aq)
If we look at the reaction above, strontium atom was dissolved in hydrochloric acid. The strontium atom is now oxidized by the acid to give Sr^2+ ion according to the equation shown above.
