The weight of a body of certain mass become zero in space.why?

Physics

2 answers:

andreyandreev [35.5K]2 years ago

6 0

Answer:

It is because of gravity that your weight of a certain mass becomes zero in space.

Explanation:

Nady [450]2 years ago

3 0

Answer:

There is no force in space.

Explanation:

Weight is the gravitational force acting on the mass as in space there is no gravity so weight appeares as zero

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An ant moves towards the plane mirror with speed of 2 m/s & the mirror is moved towards the ant with the same speed. What is

Stells [14]

Speed of ant-V_a=2m/s
Speed of mirror =v_b=2m/s

We know

$\boxed{\sf Relative\:velocity(V_{AB})=V_A-V_B}$

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6 0

2 years ago

A neutron at rest decays (breaks up) to a proton and an electron. Energy is released in the decay and appears as kinetic energy

SashulF [63]

Answer:

$5.444\times 10^{-4}$

Explanation:

The momentum of the neutron before and after the decay is the same since there's no external force.

$P_{sys}=const\\\\P=mv\\\\K=0.5mv^2$

#The neutron is initially at rest, so after the decay:

$P_A+P_B=0\\\\P_A=-P_B$

#After decay, the proton has +ve direction with a velocity $v_A$ while the electron moves in a negative direction with a velocity $v_B$

Therefore:

$P_A=m_Av_A, P_B=m_Bv_B\\\\\therefore m_Av_A,=m_Bv_B$

Let the energy released during the decay be Q:

$Q=K_{tot}=K_A+K_B\\\\Q=K_A+0.5m_Bv_B^2\\\\Q=K_A+0.5m_B(\frac{m_A}{m_B})^2v_A^2\\\\\ But \ K_A=0.5m_Av_A^2\\\\\therefore Q=K_A+\frac{m_A}{m_B}K_A=K_A(1+\frac{m_A}{m_B})\\\\=Q=\frac{m_A+m_B}{m_B}K_A\\\\m_A=1836m_B\\\\\frac{K_A}{Q}=\frac{m_B}{1836m_B+m_B}=\frac{1}{1837}\\\\\frac{K_A}{Q}=5.444\times10^{-4}$