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earnstyle [38]
1 year ago
12

Given: ∠BCD is right; BC ≅ DC; DF ≅ BF; FA ≅ FE Triangles A C D and E C B overlap and intersect at point F. Point B of triangle

E C B is on side A C of triangle A C D. Point D of triangle A C D is on side C E of triangle E C D. Line segments B C and C D are congruent. Line segments B F and F D are congruent. Line segments A F and F E are congruent. Which relationships in the diagram are true? Select three options. △ACF ≅ △ECF by HL ΔCBF ≅ ΔCDF by SSS ΔBFA ≅ ΔDFE by SAS ΔCFD ≅ ΔEFD by SSS ΔCBE ≅ ΔCDA by HL

Mathematics
2 answers:
Aloiza [94]1 year ago
4 0

Answer:

1) ΔCBF ≅ ΔCDF by (SSS)

2) ΔBFA ≅ ΔDFE by (SAS)

3) ΔCBE ≅ ΔCDA by (HL)

Step-by-step explanation:

1) Since BC ≅ DC and DF ≅ BF where CF ≅ CF (reflective property) we have;

ΔCBF ≅ ΔCDF by Side Side Side (SSS) rule of congruency

2) Since DF ≅ BF and FA ≅ FE where ∠DFE = ∠BFA (alternate angles)

Therefore;

ΔBFA ≅ ΔDFE by Side Angle Side (SAS) rule of congruency

3) Since FA ≅ FE and DF ≅ BF then where EB = FE + BF and AD = FA + DF

Where:

EB and AD are the hypotenuse sides of ΔCBE and ΔCDA respectively

We have that;

EB = AD from  FE + BF = FA + DF

Where we also have BC ≅ DC

Where:

BC and DC are the legs of ΔCBE and ΔCDA respectively

Then we have the following relation;

ΔCBE ≅ ΔCDA by Hypotenuse Leg (HL).

MatroZZZ [7]1 year ago
4 0

Answer:

B, C, E

Step-by-step explanation:

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Number of stocks held = 30
Price at which each shares of Lofty Cheese Company bought = 20 1/4
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Price at which each shares of Lofty Cheese Company sold = 25 1/4
                                                                                             = (101/4) dollars
Amount of profit made per share of Lofty Cheese Company = [(101/4 - (81/4)] dollars
                                                                                                 = (20/4) dollars
                                                                                                 = 5 dollars
Amount of profit made for 30 shares of Lofty Cheese Company = (30 * 5) dollars
                                                                                                       = 150 dollars.
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3 0
2 years ago
A high school track is shaped as a rectangle with a half circle on either side.
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Answer:

Step-by-step explanation:

perimeter=2(85)+π(12.5)=220+2×12.5π

=170+25×3.14

=170+78.5

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2 years ago
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A composite figure is comprised of a square, trapezoid, and a rectangle. The square has side lengths of 10 centimeters. The trap
Evgesh-ka [11]

The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

Step-by-step explanation:

The given is,

                   Dimensions of square has length of 10 cm

                   Trapezoid has base lengths of 8 cm and 14 cm

                   The length of the trapezoid is 4 cm

                   Rectangle has side length of 20 cm and 6 cm

Step:1

            Area of composite figure = Area of square + Area of Trapezoid

                                                                + Area of rectangle.......................(1)

Step:2

                  Formula for area of square,

                                                 A_{square} = a^{2}

                 where, a - side of length = 10 cm

                                                             =10^{2}

                                                            =100

                    Area of square, A_{square} = 100 Square centimeter

Step:3

                Formula for area of Trapezoid,

                                            A_{Trapezoid} = \frac{a+b}{2} h.......................................(2)

                    Where, a - 8 cm

                                 b - 14 cm

                                 h - 4 cm

                 From equation (2)

                                                            = \frac{8+14}{2} 4

                                                            = (11)(4)

                                                            = 44

         Area of  Trapezoid, A_{Trapezoid} = 44 square centimeters

Step:4

             Formula for area of rectangle,

                                            A_{Rectangle} =lb......................................(3)

            Where, l = 20 cm

                        b = 6 cm

           Equation (3) becomes,

                                                            = (20)(6)

                                                            = 120

            Area of rectangle, A_{Rectangle} = 120 square centimeters

Step:5

            From Equation (1),

                     A_{Composite} = 100 + 44 + 120

                                     = 264 square centimeters

Result:

            The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

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