Answer : Mechanical advantage of the machine is 0.1
Explanation :
The force applied on to a machine is 250 N. This is the input force that is applied to the machine.
The machine applies a force of 25 N to an object. This shows the output force that is applied by the machine.
Mechanical advantage of the machine is defined as the ratio of the output force and the input force.
The correct option is (A) " 0.1 "
Hence, this is the required solution.
Answer:
No, the farmer is not able to move the mule.
Explanation:
Mass =100 kg
Force=F=800 N
The coefficient between the mule and the ground=
Static friction force,f=
Normal force=N=mg
Static friction force,f=
Using
F<f
Static friction force is greater than applied force.
Therefore , the farmer is not able to move the mule.
Answer:
L' = 1.231L
Explanation:
The transmission coefficient, in a tunneling process in which an electron is involved, can be approximated to the following expression:
L: width of the barrier
C: constant that includes particle energy and barrier height
You have that the transmission coefficient for a specific value of L is T = 0.050. Furthermore, you have that for a new value of the width of the barrier, let's say, L', the value of the transmission coefficient is T'=0.025.
To find the new value of the L' you can write down both situation for T and T', as in the following:
Next, by properties of logarithms, you can apply Ln to both equations (1) and (2):
Next, you divide the equation (3) into (4), and finally, you solve for L':
hence, when the trnasmission coeeficient has changes to a values of 0.025, the new width of the barrier L' is 1.231 L
The correct answer to the question is-
CALCULATION:
As per the question, the electric field generated by the source charge is 1236 N/C at a distance of 4 m.
Hence , electric field E = 1236 N/C.
The distance of the point R = 4m
We are asked to calculate the charge possessed by the source.
The electric field produced by a source charge of Q at a distance R is calculated as -
Electric field E =
Here, is called the absolute permittivity of the free space.
Hence, the charge of source is calculated as -
Q =
=
=
=
=
Hence, the charge of source is