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2 years ago

A silver ring has a mass of 138.45 g. how many calories of heat are required to increase the temperature from 11.8 c to 162.5 c?

1 answer:

7 0

The heat required to raise a certain mass of a substance at a temperature is calculated through the equation,
heat = mass x specific heat x (T₂ - T₁)
The specific heat of silver is 0.057 cal/g⁰C
Substituting the known values to the equation,
heat = (138.45 g)(0.057 cal/g⁰C)(162.5⁰C - 11.8⁰C)
heat = 1189.27 cal

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In the 1980s, there was an international agreement to destroy all stockpiles of mustard gas, ClCH2CH2SCH2CH2Cl. When this substa

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Answer:

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Explanation:

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2 years ago

Three samples of gas each exert 740 mm hg in separate 2 L containers what pressure do they exert if they are all placed in a sin

Nesterboy [21]

Answer:

P(total) = 1110 mmHg

Explanation:

According to the Dalton law of partial pressure,

The pressure exerted by mixture of gases are equal to the sum of partial pressure of individual gases.

P(total) = P1 + P2 + P3+ .....+ Pn

Given data:

Sample A = 740 mmHg

Sample B = 740 mmHg

Sample C = 740 mmHg

Total pressure = ?

Solution:

Sample A:

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

P₂ = 370 mmHg

Sample B:

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

P₂ = 370 mmHg

Sample C:

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

P₂ = 370 mmHg

Total pressure:

P(total) = P1 + P2 + P3

P(total) = 370 mmHg + 370 mmHg+ 370 mmHg

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2 years ago

Some versions of the periodic table show hydrogen at the top of Group 1A(1) and at the top of Group 7A(17). What properties of h

lawyer [7]

Answer:Hydrogen is placed such because it exhibits some similar characteristics of both group1 and group VII elements.

Explanation:

The reason why hydrogen is similar to group 1 metals:

#It has same valence electron and inorder achieve octet state it can lose that electron and forms H+ ion

#It acts as a good reducing agent similar to group1 metals

#It can also halides

Similarity to halogens:

#hydrogen can also gain one electron to gain noble gas configuration. It can combine with other non metals to form molecules with covalent bonding.

#It exists as diatomin molecule,H2

#Have the same electronegativity nature

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2 years ago

When one atom loses an electron and another atom accepts that electron a(n) bond between the two atoms results?

morpeh [17]

When an element losses its electron its called a cation. When an element accepted that electron it called anion. This is called an ionic bond.

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2 years ago

) Do you think the pH of 1,0 M tri-methyl ammonium (CH3)3NH+, pKa = 9.80, will be higher or lower than that of 1.0 M phenol, C6H

Elanso [62]

Answer:

1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).

2. The difference in pH values is 4.95.

Explanation:

1. The pH of a compound can be found using the following equation:

$pH = -log([H_{3}O^{+}])$

First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.

Trimethyl ammonium:

We can calculate [H₃O⁺] using the Ka as follows:

(CH₃)₃NH⁺ + H₂O → (CH₃)₃N + H₃O⁺

1.0 - x x x

$Ka = \frac{[(CH_{3})_{3}N][H_{3}O^{+}]}{[(CH_{3})_{3}NH^{+}]}$

$10^{-pKa} = \frac{x*x}{1.0 - x}$

$10^{-9.80}(1.0 - x) - x^{2} = 0$

By solving the above equation for x we have:

x = 0.097 = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(0.097) = 1.01$

Phenol:

C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺

1.0 - x x x

$Ka = \frac{[C_{6}H_{5}O^{-}][H_{3}O^{+}]}{[C_{6}H_{5}OH]}$

$10^{-10} = \frac{x^{2}}{1.0 - x}$

$1.0 \cdot 10^{-10}(1.0 - x) - x^{2} = 0$

Solving the above equation for x we have:

x = 9.96x10⁻⁶ = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(9.99 \cdot 10^{-6}) = 5.00$

Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.

2. The difference in pH values for the two acids is:

$\Delta pH = pH_{C_{6}H_{5}OH} - pH_{(CH_{3})_{3}NH^{+}} = 5.00 - 1.01 = 4.95$

Therefore, the difference in pH values is 4.95.

I hope it helps you!

7 0

2 years ago