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Lana71 [14]
2 years ago
7

Which is a use for clay? ceramics batteries plaster chalk ED2020

Chemistry
2 answers:
PIT_PIT [208]2 years ago
7 0

Answer:

Because of these properties, clay is used for making pottery, both utilitarian and decorative, and construction products, such as bricks, wall and floor tiles. Different types of clay, when used with different minerals and firing conditions, are used to produce earthenware, stoneware, and porcelain

pls mark as branliest

rodikova [14]2 years ago
5 0

A. Ceramics

(A)

Have a good day

                        -DEVIL

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The electron in a ground-state H atom absorbs a photon of wavelength 97.20 nm. To what energy level does it move?
Lunna [17]

Answer:

E = h v = 6.626 x 10^{-34} x 97.20 x 10^{-9} = 6.44 x 10^{-41} J = 4.01 x 10^{-22} eV

n = Energy Level = -E^{0} / E = -13.6 / 4.01 x 10^{-22} = 3.39 x 10^{22} = 1.84 x 10^{11} energy level...

7 0
2 years ago
Calculate the empirical formula for each of the following substances. (Express answer as a chemical formula) 1) 2.90 g of Ag and
exis [7]

Answer:

1) Ag3N

2)Na2S

3)NaHSO4

4) KNO3

Explanation:

We divide each mass by the element's relative atomic mass

1) 2.90/108-Ag, 0.125/14-N

0.027-Ag, 0.0089-N

Divide by the lowest ratio

0.027/0.0089-Ag, 0.0089/0.0089 N

3-Ag, 1-N

Empirical formula- Ag3N

2)2.22/23-Na, 1.55/32-S

0.097-Na, 0.048-S

Divide by the lowest ratio

0.097/0.048-Na, 0.048/0.048-S

2-Na, 1-S

Empirical formula- Na2S

3) 2.11/23-Na, 0.0900/1-H, 2.94/32-S,5.86/16-O

0.09-Na, 0.09-H, 0.09-S,0.366-O

Divide by the lowest ratio

0.09/0.09-Na, 0.09/0.09-H, 0.09/0.09-S, 0.366/0.09-O

1-Na, 1-H, 1-S, 4-O

Empirical formula- NaHSO4

4)1.84/39, 0.657/14-N, 2.25/16-O

0.047-K, 0.047-N, 0.14-O

Divide through by the lowest ratio

0.047/0.047-K, 0.047/0.047-N, 0.14/0.047-O

1-K, 1-N, O-3

Empirical formula- KNO3

4 0
2 years ago
The general term for a large molecule made up of many similar subunits is
Setler79 [48]
A) Polymer is the general name of large units made of many smaller units (these would be called monomers). An example is starch, this is a carbohydrate polymer that is made up of smaller units (monomers) called glucose.
6 0
2 years ago
The composition of dry air at sea level is 78.03% N2, 20.99% O2, and 0.033% CO2 by volume. (a) calculate the average molar mass
levacccp [35]

Answer:

the average molar mass of this air sample can be calculated as

addition of the product of the average molar weights of the component gases and their percentage compositions

1. Average Molar mass of Air = 0.7803 x 28 + 0.2099 x 32 + 0.00033 x 44 = 28.58g/mol

2. The partial pressures of N2, O2, and CO2 in atm.

From Ideal gas law, at stp, Volume of air V=22.4L/mol

PV =nRT

Since, at constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of the gas

Total Pressure P=1atm

Partial Pressure p = mol fraction x P

Volume of N2 = 0.7803 x 22.4L = 17.47L, Partial Pressure = 0.7803atm

Volume of O2 = 0.2099 x 22.4L = 4.68L  Partial Pressure = 0.209atm

Volume of CO2 = 0.00033 x 22.4L = 0.00739L, Partial Pressure = 0.033atm

7 0
2 years ago
The burning of 80.3 g of SiH4 at constant pressure gives off 3790 kJ of heat. Calculate △H for this reaction. SiH4(g) + 2O2(g) ⟶
Trava [24]

Answer  : The value of ΔH for this reaction is, -1516 kJ/mol

Explanation :

First we have to calculate the moles of SiH_4

\text{Moles of }SiH_4=\frac{\text{Mass of }SiH_4}{\text{Molar mass of }SiH_4}

\text{Moles of }SiH_4=\frac{80.3g}{32.12g/mol}

\text{Moles of }SiH_4=2.5mol

Now we have to calculate the ΔH for this reaction.

As, 2.5 mole of SiH_4 react to gives heat = -3790 kJ

So, 1 mole of SiH_4 react to gives heat = -\frac{3790kJ}{2.5mol}

                                                                                = -1516 kJ/mol

Therefore, the value of ΔH for this reaction is, -1516 kJ/mol

7 0
2 years ago
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