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2 years ago

Which could cause topsoil to be lost? a) wind and water erosion b)lack of use c)compaction d)desertification

Chemistry

2 answers:

BlackZzzverrR [31]2 years ago

3 0

Answer:

Which could cause topsoil to be lost?

<u>a) wind and water erosion</u>

Explanation:

A natural and common cause of soil erosion is Water. Water can carry away tiny soil particles.

Raindrops can impact the soil surface and can break down the aggregates in soil and scatter them.

Water runoff is another cause of soil erosion and this occurs when water on a slope isn’t absorbed into the soil or becomes trapped on the surface.

Loose particles can be picked up and carried away by the wind.

Soil surfaces can be worn down when struck by airborne particles carried by the wind.

B. Lack of use of the top soil rather helps the top soil to regain its nutrients.

c. Compaction can the topsoil from losing particles, since there are no loose particles to be picked up.

D. Desertification mostly causes the soil to lose its nutrients, not go away completely.

Hope this helps!

alukav5142 [94]2 years ago

3 0

Answer:

The correct answer is A

Explanation:

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Answer:

Only 3 is correct.

Explanation:

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In a face-centered cubic cell (FCC) all angles are 90º and all lengths are equal. Each cubic cell has 8 atoms in each corner of the cube, and that atom is shared with 8 neighboring cells. So for a metal crystal, the atom is located at each of the eight lattice points, where it is shared equally between eight unit cells.

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a scale-model mound made of the same materials that make the real hill

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A sample of an unknown compound with a mass of 0.847 g has the following composition: 50.51 % fluorine and 49.49 % iron. When th

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Answer: 0,4278g of F and 0,4191g of Fe

Explanation: it's possible to calculate the mass of each element by multiplying the percentage (decimal) of the element by the mass of the compound.

For Fluorine (F)

0,847g * 0,5051 = 0,4278g of F

For iron (Fe)

0,847 * 0,4949 = 0,4191g of Fe

This is determined because even when the compound is decomposed, due to conservative law of mass, the decomposition process do not affect the amount of matter, so the mass of the elements remain even if they are separated from the original molecule.

At the end, the sum of the elements masses should be the total mass of the compound.

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You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number

irina1246 [14]

Answer: $9.11\times 10^{-31}kg$

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant.

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

All zero’s preceding the first integers are never significant.

Thus $9.11\times 10^{-31}kg$ has three significant figures

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2 years ago

A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a

Nata [24]

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

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23,403g - 22,652g = 0,751g.

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As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g × $\frac{1mol}{159,609g}$ = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

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As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g × $\frac{1mol}{18,02g}$ = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

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2 years ago