A package is dropped from a helicopter moving upward at 1.5 m/s. If it takes 16.0 s before the package strikes the ground, how h

Question

Yuliya22 [10]

2 years ago

12

A package is dropped from a helicopter moving upward at 1.5 m/s. If it takes 16.0 s before the package strikes the ground, how h

igh above the ground was the package when it was released if air resistance is negligible?

Physics

1 answer:

pashok25 [27] · Answer 1 · 2023-10-07T15:21:03+03:00

Well we know acceleration from free fall due to gravity is 9.8m/s^2

Lay out

S = displacement is what we need

U

V = 1.5m/s

A = 9.8m/s2

T = 16.0s

Use the equation s=vt-1/2at^2

Where a = acceleration t= time and v= velocity

Sub in the values to get displacement or height from ground

= -1230.4 metres which would be positive as you’re measuring distance (scalar quantity) so it’s 1230.4 metres