We can solve the problem by using Snell's law, which states

where

is the refractive index of the first medium

is the angle of incidence

is the refractive index of the second medium

is the angle of refraction
In our problem,

(refractive index of air),

and

(refractive index of carbon disulfide), therefore we can re-arrange the previous equation to calculate the angle of refraction:

From which we find
Please post in English so i or someone else can help you.
Answer:
514 cal
Explanation:
In order to calculate the lost heat by the amount of water you first take into account the following formula:
(1)
Q: heat lost by the amount of water = ?
m: mass of the water
c: specific heat of water = 1cal/g°C
T2: final temperature of water = 11°C
T1: initial temperature = 12°C
The amount of water is calculated by using the information about the density of water (1g/ml):

Then, you replace the values of all parameters in the equation (1):

The amount of water losses a heat of 514 cal
Answer: a) 95.07m b) 81.88 m
Explanation:
a)
For finding the distance when vehicle is going downhill we have the formula as:
Stop sight distance= Velocity*Reaction time + Velocity² / 2*g*(f constant- Grade value)
Now by AASHTO, we have for v= 45 mph= 72.4 kph, f= 0.31
Reaction time= 0.28
So putting values we get
Stop sight distance= 0.28*72.4 *1 + 
Stop sight distance= 95.07 m
b)
For finding the distance when vehicle is going uphill we have the formula as:
Stop sight distance= Velocity*Reaction time + Velocity² / 2*g*(f constant- Grade value)
Now by AASHTO, we have for v= 45 mph= 72.4 kph, f= 0.31
Reaction time= 0.28
So putting values we get
Stop sight distance= 0.28*72.4 *1 + 
Stop sight distance= 81.88 m
Answer:
v = 36.667 m/s
Explanation:
Knowing the rotational inertia as
Lₙ = 550 kg * m²
r = 1.0 m
m = 30.0 kg
To determine the minimum speed v must have when she grabs the bottom
Lₙ = I * ω
I = ¹/₂ * m * r²
I = ¹/₂ * 30.0 kg * 1.0² m
I = 15 kg * m²
Lₙ = I * ω ⇒ ω = Lₙ / I
ω = [ 550 kg * m² /s ] / ( 15 kg * m² )
ω = 36.667 rad /s
v = ω * r
v = 36.667 m/s