Question

A person places his hand palm downward on a scale and pushes down on the scale until it reads 96.0 N. The triceps muscle is responsible for this arm extension force. Find the force exerted by the triceps muscle. The bottom of the triceps muscle is 2.50 cm to the left of the elbow joint, and the palm is pushing at approximately 31.0 cm to the right of the elbow joint.

Answer 1

Answer:

the force exerted by the triceps muscle is 1190.4 N or 1.2 kN

Explanation:

given data

F = 96 N

D = 2.50 cm

L = 31 cm

solution

we will apply here equilibrium  condition that is

∑r = about the elbow joint    ............................1

so force exert by the muscle is

F(tri) × D = F × L     .................2

put here value

F(tri) × 2.50 = 96 × 31

solve it we get

F(tri) = 1190.4 N

so the force exerted by the triceps muscle is 1190.4 N or 1.2 kN