A positive charge moves in the direction of an electric field. Which of the following statements are true?
2 answers:
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Answer:
the direction that should be walked by Ricardo to go directly to Jane is 23.52 m, 24° east of south
Explanation:
given information:
Ricardo walks 27.0 m in a direction 60.0 ∘ west of north, thus
A= 27
Ax = 27 sin 60 = - 23.4
Ay = 27 cos 60 = 13.5
Jane walks 16.0 m in a direction 30.0 ∘ south of west, so
B = 16
Bx = 16 cos 30 = -13.9
By = 16 sin 30 = -8
the direction that should be walked by Ricardo to go directly to Jane
R = √A²+B² - (2ABcos60)
= √27²+16² - (2(27)(16)(cos 60))
= 23.52 m
now we can use the sines law to find the angle
tan θ =
= By - Ay/Bx -Ax
= (-8 - 13.5)/(-13.9 - (-23.4))
θ = 90 - (-8 - 13.5)/(-13.9 - (-23.4))
= 24° east of south
Answer:
-5.1 kg m/s
Explanation:
Impulse is the change in momentum.
Change in momentum= final momentum - initial momentum=m +m
Plugging in the values= -0.15*24 - (0.15*10) (The motion towards the pitcher is negative as the initial motion is considered to be positive)
Impulse=-5.1 kg m/s (-ve means that it is the impulse towards the pitcher)
Answer:
a.
b.
Explanation:
The force existing between two charges is given as
where q= charge,
k=constant
r= distance between the two charges
Note: this force can either be repulsive or attractive force depending on the charges involve. it is repulsive if they are similar charge and it is attractive if it is opposite charges.
Also the charge of an electron is
A. we first determine the magnitude force between the -4nC and the electron
this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis
for the -5.50nC the distance between them is 0.600m as can be seen in the diagram the magnitude of the force is
this this force will be repulsive force and it points away from the electron i.e points towards the -ve x-axis.
The total net force on the electron is thus
b. at distance of x=1.20m, this is shown on the diagram below (attachment 2)
we first determine the magnitude force between the -4nC and the electron
this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.
for the -5.50nC the distance between them is 0.4m as can be seen in the diagram the magnitude of the force is
this this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.
The total net force on the electron is thus
