Answer:
The turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.
Ten years after the conservation measures are implemented the population will be 3260 turtles.
Step-by-step explanation:
To find the rate of growth of the turtle population at any time <em>t</em> you need to find 
In particular, when t = 2 and t = 6, we have
so the turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.
The turtle population at the end of the tenth year will be
Add the two equations and use the elimination method. The x term will "cancel out" to be able to solve for the y term.
STEP 1
−12x−5y=40
12x−11y=88
x terms "cancels out"; add y terms
-16y= 128
divide both sides by -16
y= -8
STEP 2
substitute y value into either original equation
12x−11y=88
12x - 11(-8)= 88
12x + 88= 88
subtract 88 from both sides
12x= 0
divide both sides by 12; 0 divided by any number is 0
x= 0
ANSWER: x= 0; y= -8
Hope this helps! :)
Answer:
The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.
Step-by-step explanation:
The data provided is as follows:
25 to 34 45 to 54
1329 2268
1906 1965
2426 1149
1826 1591
1239 1682
1514 1851
1937 1367
1454 2158
Compute the mean and standard deviation for the group "25 to 34" as follows:
![\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%20x%3D%5Cfrac%7B1%7D%7B8%7D%5Ctimes%20%5B1329%2B1906%2B...%2B1454%5D%3D%5Cfrac%7B13631%7D%7B8%7D%3D1703.875%5C%5C%5C%5Cs%3D%5Csqrt%7B%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x-%5Cbar%20x%29%5E%7B2%7D%7D%3D%5Csqrt%7B%5Cfrac%7B1%7D%7B8-1%7D%5Ctimes%201086710.875%7D%3D394.01)
Compute the <em>z</em>-score for the group "25 to 34" as follows:
Compute the mean and standard deviation for the group "45 to 54" as follows:
![\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%20x%3D%5Cfrac%7B1%7D%7B8%7D%5Ctimes%20%5B2268%2B1965%2B...%2B2158%5D%3D%5Cfrac%7B14031%7D%7B8%7D%3D1753.875%5C%5C%5C%5Cs%3D%5Csqrt%7B%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x-%5Cbar%20x%29%5E%7B2%7D%7D%3D%5Csqrt%7B%5Cfrac%7B1%7D%7B8-1%7D%5Ctimes%201028888.875%7D%3D383.39)
Compute the <em>z</em>-score for the group "45 to 54" as follows:
Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.
Answer:
she has 12 - D quarters.
She has 24 (12-D) cents in quarters
Step-by-step explanation:
You know that the number of coins, and you know the number of dimes - even if the amount is a variable - you can find the amount of quarters with an equation.
If you knew that Lina had 6 dimes instead of D, you would say 12 - 6 and get the number of quarters. You can do the same thing here.
and If you know Lina has 6 quarters, you could find the amount of money in cents by multiplying 6 by 25. You can do that here too, but with variables and an equation.
Answer: 60%
Step-by-step explanation: 24/40 = .6 x 100 = 60
