<span>4x^2y + 12xy^2 + 9y^3</span>
Answer: The combined area of the shaded triangles in Figure one is equal to the combined area of the shadead triangles in figure 2. The area of the unshaded square in Figure 1 can be represented by c^2. The combined area of the two unshaded squares in Figure 2 can be represented by a^2+b^2. The areas of the squares in Figure 1 and Figure 2 who that a^2+b^2=c^2.
Step-by-step explanation:
I‘m taking the test.
Answer:
Step-by-step explanation:
There are a couple of ways to solve this, depending on what you already know.
Point-Slope Form
where <em>m</em> is the slope and 
is a point on the line.
First, calculate the slope using the two given points 
.
.
Fill in the point-slope pattern
There's the equation in slope-intercept form (
).
Slope-Intercept Form
Use directly.
Find the slope just like the above, so 
.
Now, plug one of the points (either one!) together with <em>m</em> into
Now you know the value of <em>b</em>, so the equation for the line is
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
