The given question is incomplete, the complete question is as follows:
Our text describes a trade-off that we must make as engineers between our confidence in the value of a parameter versus the precision with which we know the value of that parameter. That trade-off might be affected by whether we are looking at a two-sided or bounded (one-sided) interval.
Question: Discuss your interpretation of the confidence-precision trade-off, and provide a few examples of how you might make a choice in one direction or the other in an engineering situation.
Answer: A balancing point is required to be reached to obtain a better confidence level in the predicted values.
Explanation:
The confidence interval and precision are the two terms that aims at providing the accurate estimation of the measurability of an object. If the precision increases, we can compromise on the confidence level and if the confidence level increases, then the precision of the predicted value also dilutes.
Thus a balance point is required to be reached between these two variables so that we get better confidence in the values being predicted without losing the correct estimation on precision. Ensuring that both the confidence and precision are maintained.
Answer:
hello the diagram attached to your question is missing attached below is the missing diagram
answer :
a) 48.11 MPa
b) - 55.55 MPa
Explanation:
First we consider the equilibrium moments about point A
∑ Ma = 0
( Fbd * 300cos30° ) + ( 24sin∅ * 450cos30° ) - ( 24cos∅ * 450sin30° ) = 0
therefore ;<em> Fbd = 36 ( cos ∅tan30° - sin∅ ) kN ----- ( 1 )</em>
A ) when ∅ = 0
Fbd = 20.7846 kN
link BD will be under tension when ∅ = 0, hence we will calculate the loading area using this equation
A = ( b - d ) t
b = 12 mm
d = 36 mm
t = 18
therefore loading area ( A ) = 432 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd = 
= 20.7846 kN / 432 mm^2 = 48.11 MPa
b) when ∅ = 90°
Fbd = -36 kN
the negativity indicate that the loading direction is in contrast to the assumed direction of loading
There is compression in link BD
next we have to calculate the loading area using this equation ;
A = b * t
b = 36mm
t = 18mm
hence loading area = 36 * 18 = 648 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd = = -36 kN / 648mm^2 = -55.55 MPa
Answer:
Weight(lb): 10
Flat fee(cents): 75
Cents per pound: 25
Shipping cost(cents): 325
Explanation:
we run this as a jave programming language
import java.util.Scanner;
public class Shipping Calculator {
public static void main (String [] args) {
int shipWeightPounds = 10;
int shipCostCents = 0;
final int FLAT_FEE_CENTS = 75;
final int CENTS_PER_POUND = 25;
shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPound
/* look up the solutioin above */
System.out.println("Weight(lb): " + shipWeightPounds);
System.out.println("Flat fee(cents): " + FLAT_FEE_CENTS);
System.out.println("Cents per pound: " + CENTS_PER_POUND);
System.out.println("Shipping cost(cents): " + shipCostCents);
}
}
Answer:
#Initialise a tuple
team_names = ('Rockets','Raptors','Warriors','Celtics')
print(team_names[0])
print(team_names[1])
print(team_names[2])
print(team_names[3])
Explanation:
The Python code illustrates or printed out the tuple team names at the end of a season.
The code displayed is a function that will display these teams as an output from the program.
