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2 years ago

Identify the solutions that will form a precipitate when mixed with aqueous barium chloride, BaCl2 (aq). Select all that apply.

Chemistry

1 answer:

Lemur [1.5K]2 years ago

3 0

The given question is incomplete, the complete question is:

Identify the solutions that will form a precipitate when mixed with aqueous barium chloride, BaCl2 (aq). Select all that apply. potassium carbonate, K2CO3 (aq) silver nitrate, AgNO3(aq) sulfuric acid, H2SO4 (aq) sodium hydroxide, NaOH(aq) sodium chloride, NaCl (aq) copper(II) nitrate, Cu(NO3)2 (aq)

Answer:

The aqueous solution of BaCl2 form precipitate with potassium carbonate, silver nitrate, sulfuric acid and sodium hydroxide.

Explanation:

The formation of an insoluble salt, which takes place when two solutions comprising soluble salts are reacted with each other, the reaction is termed as precipitation reaction. The insoluble salt produced in the given reaction is termed as the precipitate.

BaCl₂ reacts with K₂CO₃ to produce white precipitate in the form of BaCO₃,

BaCl₂ (aq) + K₂CO₃ (aq) ⇒ BaCO₃ (s) + 2KCl (aq)

BaCl₂ reacts with H₂SO₄ to produce white precipitate in the form of BaSO₄,

BaCl₂ (aq) + H₂SO₄ (aq) ⇒ BaSO₄ (s) + 2HCl (aq)

BaCl₂ (aq) reacts with NaOH to produce white precipitate in the form of Ba(OH)2,

BaCl₂ (aq) + 2NaOH (aq) ⇒ Ba(OH)2 (s) + 2NaCl (aq)

BaCl₂ reacts with AgNO₃ to produce white precipitate in the form of 2AgCl (s),

BaCl₂ (aq) + 2AgNO₃ (aq) ⇒ Ba(NO₃)₂ (aq) + 2AgCl (s)

Upon reaction of BaCl₂ with Cu(NO₃)₂ no formation of precipitate takes place, and BaCl₂ does not react with NaCl.

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Room temperature is about 20 degrees Celsius. Explain how you could convert this temperature to kelvin. Use evidence from the fi

Taya2010 [7]

Answer:

293.15 K.

Explanation:

It is given that, the room temperature is 20 degrees Celsius.

We need to convert this temperature into kelvin.

The conversion from degrees Celsius to Kelvin is as follows :

$T_k=T_c+273.15$

We have, $T_c=20^{\circ} C$

So,

$T_k=20+273.15\\\\T_k=293.15\ K$

So, the room temperature is 293.15 kelvin.

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2 years ago

The molecular weight of table salt, NaCl, is 58.5 g/mol. A tablespoon of salt weighs 6.37 grams. Calculate the number of moles o

dezoksy [38]

A: 6.37gNaCl

B: 1 mol NaCl

C: 58.5 g NaCl

These answers are correct on e2020 I just got them right.

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2 years ago

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What is the change in enthalpy in kilojoules when 3.24 g of CH3OH is completely reacted according to the following reaction 2 CH

vodka [1.7K]

Answer:

12.78 kJ

Explanation:

The correct balanced reaction would be

$2CH_3OH\rightarrow 2CH_4+O_2\Delta H=252.8\ \text{kJ}$

Mass of methanol = $3.24\ \text{g}$

Moles of methanol can be obtained by dividing the mass of methanol with its molar mass $(32.04\ \text{g/mol})$

$\dfrac{3.24}{32.04}=0.10112\ \text{moles}$

Enthalpy change for the number of moles is given by

$\dfrac{\text{Number of moles of methanol in the reaction}}{\text{Enthalpy change in the reaction}}=\dfrac{\text{Number of moles in 3.24 g of methanol}}{\text{Enthaply in change in the mass of methanol}}$

$\\\Rightarrow\dfrac{2}{252.8}=\dfrac{0.10112}{\Delta H}\\\Rightarrow \Delta H=\dfrac{0.10112\times 252.8}{2}\\\Rightarrow \Delta H=12.781568\approx 12.78\ \text{kJ}$

The change in enthalpy is 12.78 kJ.

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2 years ago

How many milliliters of C5H8 can be made from 366 mL C5H12 ?

zlopas [31]

The number of Ml of C₅H₈ that can be made from 366 ml C₅H₁₂ is 314.7 ml of C₅H₈

<u><em>calculation</em></u>

step 1: write the equation for formation of C₅H₈

C₅H₁₂ → C₅H₈ + 2 H₂

Step 2: find the mass of C₅H₁₂

mass = density × volume

= 0.620 g/ml × 366 ml =226.92 g

Step 3: find moles Of C₅H₁₂

moles = mass÷ molar mass

from periodic table the molar mass of C₅H₁₂ = (12 x5) +( 1 x12) = 72 g/mol

moles = 226.92 g÷ 72 g/mol =3.152 moles

Step 4: use the mole ratio to determine the moles of C₅H₈

C₅H₁₂:C₅H₈ is 1:1 from equation above

Therefore the moles of C₅H₈ is also = 3.152 moles

Step 5: find the mass of C₅H₈

mass = moles x molar mass

from periodic table the molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol

= 3.152 moles x 68 g/mol = 214.34 g

Step 6: find Ml of C₅H₈

=mass / density

= 214.34 g/0.681 g/ml = 314.7 ml

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2 years ago

Many classic experiments have given us indirect evidence of the nature of the atom. Which of the experiments listed below did no

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Answer:

Option A, The Rutherford experiment proved the Thomson "plum-pudding" model of the atom to be essentially correct.

Explanation:

Thomson's plum pudding model:

Plum pudding model was proposed by J.J Thomson. In Thomson's model, atoms are proposed as sea of positively charge in which electrons are distributed through out.

Result of Rutherford experiment:

As per Rutherford's experiment:

Most of the space inside the atom is empty.

Positively charge of the atom are concentrated in the centre of the atom known as nucleus.

Electrons are present outside the nucleus and revolve around it.

As it is clear that, result of Rutherford experiment did not supported the Thomson model.

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2 years ago