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Scilla [17]
2 years ago
9

Cynthia invested $12,000 in a savings account. If the interest rate is 6%, how much will be in the account in 10 years by compou

nding continuously? Round to the nearest cent.
Mathematics
2 answers:
sattari [20]2 years ago
6 0

Answer:

In 10 years she'll have approximately $21865.4 in her account.

Step-by-step explanation:

When an amount is compounded continuously its value over time is given by the following expression:

v(t) = v(0)*e^{rt}

Applying data from the problem gives us:

v(10) = 12000*e^{(0.06*10)}\\v(10) = 12000*e^{0.6}\\v(10) = 21865.4

In 10 years she'll have approximately $21865.4 in her account.

ValentinkaMS [17]2 years ago
5 0

Answer: A= $21,768.22

Step-by-step explanation:

Identify the values of each variable in the formulas.

A=?

P= $12,000

r= 0.06

t= 10

For quarterly composing, n=4. There are 4 quarters in a year.

A= P(1+r/n)^nt

Substitute the values in the formula

A= 12,000( 1+ 0.06/4)^4*10

Commute the amount

A= $21,768.22

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For Heidi: 5 x 3 = 15
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Answer:

5(d - 4)

Step-by-step explanation:

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2 years ago
For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7
Sloan [31]

Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

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Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean 210x^6y^4

We can deduce that this term will be located somewhere in the middle. So I will calculate k= 5; k=6 \text{ and } k =7.

For k=5

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just x^{n-k} y^k

For k=6

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

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