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Oksi-84 [34.3K]
2 years ago
8

Base your answer to the question on the information below and on your knowledge of chemistry. At 1023 K and 1 atm, a 3.00-gram s

ample of SnO2(s) (gram formula mass = 151 g/mol) reacts with hydrogen gas to produce tin and water, as shown in the balanced equation below. SnO2(s) + 2H2(g) → Sn(L) + 2H2O(g) Show a numerical setup for calculating the number of moles of SnO2(s) in the 3.00-gram sample.
Chemistry
2 answers:
o-na [289]2 years ago
8 0
To calculate for the number of moles of SnO2 in the sample, we need the value of the products from the reaction. Since we do not have that data, we can assume that all of the sample is SnO2. Then, we are given the molecular mass of the sample, 151g/mol.

So, the number of moles is 3g / 151 g/mol = 0.0199 moles SnO2
xeze [42]2 years ago
6 0

Answer:

Moles of SnO2 = 0.020

Explanation:

Given:

SnO2 (s) + 2H2(g) → Sn(l) + 2H2O(g)

Mass of SnO2 = 3.00 g

Molar mass of SnO2 = 151 g/mol

Explanation:

'Mole' refers to the amount of a given substance. It is expressed in terms of the ratio of the mass of the substance to its molar mass

Mole = \frac{Mass (g)}{Molar\ Mass (g/mol)} \\\\Moles\ SnO2 = \frac{3.00 g}{151 g/mol } = 0.0198\ moles = 0.020\ moles

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Manganese, Fifth transition element

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Explanation:

Complete Question

In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works as it does in our universe, except that there are six d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the sixth and seventh elements in the first transition series in Universe L. Note; you may use [X] to stand for the electron configuration of the noble gas at the end of the row before the first transition series.

Solution

In our universe, there are 5 d orbitals.

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The fifth and sixth transition elements in our universe is then Manganese and Iron respectively.

Manganese - [Ar] 3d⁵ 4s²

Iron - [Ar] 3d⁶ 4s²

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