The chemical equation representing the reaction between baking soda and acetic acid :
According to the Law of conservation of mass, the overall mass is conserved in a chemical reaction. That is total mass of reactants is equal to the mass of the products.
Given here Mass of Baking soda = 15 g
Mass of acetic acid = 10 g
Total mass of the reactants = 15 g +10 g = 25 g
After the reaction, total mass of products = 23 g
This difference in masses must be because one of product carbon dioxide is a gas, which is lost and hence the mass of products is lower than the mass of reactants. Therefore, the mass is conserved in this reaction.
The molar mass of anhydrous Na₂SO₄ = [2(23) + 32 + 4(16)]
= 142 g/mol
If the molar mass of hydrated Na₂SO₄ = 322 g/mol
Since hydrated salt = Anhydrous Salt + Water
Then the mass of hydration (Water)= 322 g/mol - 142 g/mol
= 180 g/mol
Since the molar mass of water itself is 18 g/mol
⇒ Moles of water = 180 g/mol ÷ 18g/mol
= 10
Thus n = 10; the formula of the hydrated salt is Na₂SO₄ · 10H₂O (Sodium Sulphate Decahydrate)
As we know that Molarity is given as,
M = moles / V
Solving for V,
V = moles / M ------------------(1)
Also, moles is equal to,
moles = mass / M. mass -------------(2)
puting value of moles from eq. 2 into eq. 1,
V = (mass / M.mass) / M
Putting values,
V = (45 g / 164 g/mol) / 1.3 mol/dm³
V = 0.21 dm³
11.43g/mL
Explanation:
Given parameters:
Volume of water in the graduated cylinder = 100mL
Volume of water + lead weight = 450mL
Mass of lead weight = 4000g
Unknown:
Density of the lead weight = ?
Solution:
Density is the mass per unit volume of a body.
Density = 
Volume of the lead weight = volume of water displaced
Volume of lead weight = 450 - 100 = 350mL
Density = 
= 11.43g/mL
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Answer:MnCO3+2H2O----->MnO2+ HCO3-+2e-+3H+
Explanation:The equation to be balanced is
MnCO3 ------> MnO2+HCO3-
The oxidation number of Mn changes from +2 in MnCO3 to +4 in MnO2
Therefore two electrons must be added to the right as shown below:
MnCO3 -------> MnO2+ HCO3-+ 2e-Now,there is one negative charge HCO3- and 1 negative charge on the two electrons making a total of -3 charges on the right. There is zero charge on the left.
To balance the equation,add3H+on the right,to cancel out the charges.
MnCO3 --------> MnO2+HCO3-+2e-+3H+
Adding H2O to balance Hydrogen and Oxygen atoms:
MnCO3+2H2O ------->MnO2+HCO3-+2e-+3H+
