Suppose a student completes an experiment with an average value of 2.9 mL and a calculated standard deviation of 0.71 mL. What i
1 answer:
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Complete Question is attached below,
Answer:
Option-A is the correct answer.
Explanation:
As we know Hydroxide contains one hydrogen and one oxygen atom. Also one negative charge is being carried bu hydroxide ion as,,,
OH⁻
Now in order to draw its lewis structure we first of all calculate the total number of valence electrons of both elements i.e.
Valence electrons in Oxygen = 6
valence electrons in Hydrogen = 1
Number of negative charges = 1
------------
Total valence electrons 8
Now, we draw both elements and connect them via a single bond and subtract 2 electrons per single bond,
= 8 - 2
= 6
Now these six electrons are added to oxygen atom as it is more electronegative element. Hence, a structure shown in Option-A is formed, and the negative charge is in fact the -1 formal charge of oxygen atom.
Answer:
Option-A is the correct answer.
Explanation:
As we know Hydroxide contains one hydrogen and one oxygen atom. Also one negative charge is being carried bu hydroxide ion as,,,
OH⁻
Now in order to draw its lewis structure we first of all calculate the total number of valence electrons of both elements i.e.
Valence electrons in Oxygen = 6
valence electrons in Hydrogen = 1
Number of negative charges = 1
------------
Total valence electrons 8
Now, we draw both elements and connect them via a single bond and subtract 2 electrons per single bond,
= 8 - 2
= 6
Now these six electrons are added to oxygen atom as it is more electronegative element. Hence, a structure shown in Option-A is formed, and the negative charge is in fact the -1 formal charge of oxygen atom.
Answer:
- Keq = 4
Explanation:
The correct statement is:
When 1 mol each of C₂H₅OH and CH₃CO₂H are allowed to react in 1 L of the solvent dioxane, equilibrium is established when 1/3 mol of each of the reactants remains. Calculate the equilibrium constant for the reaction. (Note: Water is a solute in this reaction.)
<u>1. Equilibrium equation</u>
- C₂H₅OH + CH₃CO₂H ⇄ CH₃CO₂C₂H₅ + H₂O
↑ ↑ ↑ ↑
ethanol acetic acid ethyl acetate water
<u>2. Equilibrium constant</u>
- Keq = [Products] / [Reactants], each raised to tis stoichiometrical coefficient.
Since water is also a solute in this reaction (the solvent is dioxane) its concentration will appear in the equilibrium constant.
<u>3. Equlibrium concentrations:</u>
Moles
C₂H₅OH + CH₃CO₂H ⇄ CH₃CO₂C₂H₅ + H₂O
Initial 1 1 0 0
Change -2/3 -2/3 +2/3 +2/3
End 1/3 1/3 2/3 2/3
Since the volume is 1 liter, the concentration is equal to the number of moles
<u>4. Calculations:</u>