The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as
Mg(IO3)2
MgI2O6
As we know that
Mg has +2
O has -2
So,
(+2) + 2I + 6 (-2)=0
2 + 2I - 12 =0
10+ 2I =0
10 = 2I
I =5
Boiling and melting points are physical properties because they do not change the chemical nature of the substance whose properties you are measuring.
Answer:
evaporated
Explanation:
Once the solution is evaporated there will only be salt left, since the only other thing in the soulution is water.
Answer:
A) ∆Suniv >0, ∆G<0, T∆Suniv >0.
Explanation:
The connection between entropy and the spontaneity of a reaction is expressed by the <u>second law of thermodynamics</u><u>: The entropy of the universe increases in a spontaneous process and remains unchanged in an equilibrium process</u>.
Mathematically, we can express the second law of thermodynamics as follows:
For a spontaneous process: ΔSuniv = ΔSsys + ΔSsurr > 0
Therefore, the second law of thermodynamics tells us that a spontaneous reaction increases the entropy of the universe; that is, ΔSuniv > 0.
If we want spontaneity expressed only in terms of the properties of the system (ΔHsys and ΔSsys), we use the following equation:
-TΔSuniv = ΔHsys - TΔSsys < 0
That means that T∆Suniv >0.
This equation says that for a process carried out at constant pressure and temperature T, if the changes in enthalpy and entropy of the system are such that <u>ΔHsys - TΔSsys is less than zero, the process must be spontaneous.</u>
Finally, if the change in free energy is less than zero (ΔG<0), the reaction is spontaneous in the forward direction.
Answer:
Fe is the anode and Sn is the cathode; NO3- ions flow into half-cell compartment (A) and Na ions flow into half-cell compartment (B).
Explanation:
The purpose of a salt bridge in a voltaic cell is not to move electrons from the electrolyte, it's main function is the maintenance of charge balance between the half cells .The electrons flow from the anode to the cathode.
The iron half cell which has a higher reduction potential serves as anode. Iron atoms give up electrons to form positive ions according to the equation;
Fe(s)-----> Fe^2+(aq) + 2e
Hence there will be an excess of positive ions in the anode (compartment A). NO3^- ions from the salt bridge will migrate towards this compartment to ensure charge balance.
Similarly, in compartment B(cathode) Sn^2+ ions will accept two electrons according to the reaction;
Sn^2+(aq) + 2e ------> Sn(s)
This reaction causes a depletion of positive ions in compartment B, hence Na^+ from the salt bridge move towards this compartment to ensure charge balance.
