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daser333 [38]
2 years ago
3

The ancient Greek Eratosthenes found that the Sun casts different lengths of shadow at different points on Earth. There were no

shadows at midday in Aswan as the Sun was directly overhead. 800 kilometers north, in Alexandria, shadow lengths were found to show the Sun at 7.2 degrees from overhead at midday. Use these measurements to calculate the radius of Earth.
Physics
1 answer:
Nimfa-mama [501]2 years ago
8 0

Answer:

The  radius of the earth is r =  6365.4 \ km

Explanation:

From the question we are told that

     The distance at  Alexandria is  d_a =  800 \ km  =  800 *10^{3} \  m

      The angle of the sun is  \theta =  7.2 ^o

So we want to first obtain the circumference of the earth

   So let assume that the earth is  circular (360 ^o)

  Now from question we know that the sun made an angle of 7.2 ^o so with this we will obtain how many  (7.2 ^o)  are in 360^o

 i.e    N  =  \frac{360}{7.2}

=>      N  =  50

     With this  value we can evaluate the circumference as

             c =  50 *  800

              c = 40000 \ km

Generally circumference is mathematically represented as

        c =   2\pi r

         40000 =  2 *  3.142 *  r

=>        r =  6365.4 \ km

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A fellow student of mathematical bent tells you that the wave function of a traveling wave on a thin rope is y(x,t)=2.30mmcos[(6
Shalnov [3]

Answer:

a. y(x,t)= 2.05 mm cos[( 6.98 rad/m)x + (744 rad/s).

b. third harmonic

c. to calculate frequency , we compare with general wave equation

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742/2*pi

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Explanation:

A fellow student of mathematical bent tells you that the wave function of a traveling wave on a thin rope is y(x,t)=2.30mmcos[(6.98rad/m)x+(742rad/s)t]. Being more practical-minded, you measure the rope to have a length of 1.35 m and a mass of 3.38 grams. Assume that the ends of the rope are held fixed and that there is both this traveling wave and the reflected wave traveling in the opposite direction.

A) What is the wavefunction y(x,t) for the standing wave that is produced?

B) In which harmonic is the standing wave oscillating?

C) What is the frequency of the fundamental oscillation?

a. y(x,t)= 2.05 mm cos[( 6.98 rad/m)x + (744 rad/s).

b. lambda=2L/n

when comparing the wave equation with the general wave equation , we get the wavelength to be

2*pi*x/lambda=6.98x

lambda=0.9m

we use the equation

lambda=2L/n

n=number of harmonics

L=length of string

0.9=2(1.35)/n

n=2.7/0.9

n=3

third harmonic

c. to calculate frequency , we compare with general wave equation

y(x,t)=Acos(kx+ωt)

from ωt=742t

ω=742

ω=2*pi*f

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f=118.09Hz

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