The correct answer is; She can purchase OEM codes from e-commerce sites such as Amazon or eBay.
Further Explanation:
There are some sites where OEM codes cost around 110$ or higher. it will depend on which edition of Windows she plans on purchasing. The official Microsoft website sells the codes for much higher than other e-commerce sites.
There is some ways to get the older Windows for free online using a software key from a previous purchase from a friend or one you have purchased in the past. There is also a free trial that can be used for 7 days and possibly 30 days.
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Answer:
offline backup solution
Explanation:
In such a scenario, the best option would be an offline backup solution. This is basically a local and offline server that holds all of the flight record data that the cloud platform has. This offline backup server would be updated frequently so that the data is always up to date. These servers would be owned by the aviation company and would be a secondary solution for the company in case that the cloud platform fails or the company cannot connect to the cloud service for whatever reason. Being offline allows the company to access the database regardless of internet connectivity.
Return them they are probably defective or turn ur media volume all the way down.
Answer:
Normalization
Explanation:
Converting a poorly-structured table and optimizing its database structure in order to reduce redundancy in relations can be referred to as database normalization. If the data is not redundant means that data inconsistencies and errors like deletion and insertion will get reduced or eliminated significantly.
Answer:
The most straight forward way to do it: in general string are zero index based array of characters, so you need to get the length of the string, subtract one and that will be the last character, some expressions in concrete languages would be:
In Python:
name = "blair"
name[len(name) - 1]
In JavaScript:
name = "blair"
name[name.length - 1]
In C++:
#include <string>
string name = "blair";
name[name.length() - 1];
