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2 years ago

Quadrilateral QRST is similar to quadrilateral EDGF. What's the scale factor from EDGF to QRST

Mathematics

1 answer:

mart [117]2 years ago

5 0

Answer:

C. $\frac{6}{5}$

Step-by-step explanation:

The ratio of the corresponding sides of a polygon is said to be equal. The ratio gives us the scale factor.

Therefore, assuming that quadrilateral QRST was the original polygon that was scaled up to give a similar polygon, EDGF, the scale factor would be expressed as $\frac{42}{35}$

The scale factor = $\frac{42}{35} = \frac{6*7}{5*7} = \frac{6}{5}$

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Which equation represents the volume of a cone with the same base and height as the cylinder below? A cylinder with a height k a

Igoryamba

Answer: The correct answer is Volume Cone = one-third pi t squared k

Step-by-step explanation: The first important detail to note here is that both cylinder and cone have the same base and the same height This implies that when writing out the formula for calculating the volume of either of the two shapes, the radius and the height will be the same number or value.

The volume of a cylinder is given as;

Volume cylinder = pi x r squared x h (that is πr²h)

Also the volume of a cone is given as;

Volume cone = one-third x pi x r squared x h (that is 1/3*πr²h)

However, the variables have been changed such that the radius r is now represented by t while the height h is now represented by k.

Therefore the volume of the cone should now be re-written as;

Volume cone = one-third pi t squared k <em>(that is 1/3 *πt²k)</em>

3 0

2 years ago

Read 2 more answers

Coordinates, gradient and tangent work (see image).

Ivenika [448]

Answer:

a) $P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)$

b) $4x+2h$

c) $4x$

Step-by-step explanation:

Given the curve

$y=2x^2-5$

a) If the x-coordinate of P is $x$ , then the y-coordinate is $2x^2-5,$ so point P has coordinates $(x,2x^2-5)$

If the x-coordinate of Q is $x+h$ , then the y-coordinate is $2(x+h)^2-5$ so point Q has coordinates $(x+h,2(x+h)^2-5)$

b) The gradient of the secant RQ is

$\dfrac{y_Q-y_P}{x_Q-x_P}\\ \\=\dfrac{(2(x+h)^2-5)-(2x^2-5)}{(x+h)-x}\\ \\=\dfrac{2(x+h)^2-5-x^2+5}{x+h-x}\\ \\=\dfrac{2(x+h)^2-2x^2}{h}\\ \\=\dfrac{2x^2+4xh+2h^2-2x^2}{h}\\ \\=\dfrac{4xh+2h^2}{h}\\ \\=4x+2h$

c) If $h\rightarrow 0,$ then the gradient $4x+2h\rightarrow 4x$

5 0

2 years ago

It costs $350 to rent a room for a party. You also plan to hire a caterer that charges $9.25 per person. Write and solve a linea

Rus_ich [418]

350+9.25x so it would be $905

5 0

2 years ago

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Choose the point-slope form of the equation below that represents the line that passes through the points (−6, 4) and (2, 0). y

Likurg_2 [28]

Y-y1=m(x-x1)
for slope=m
for point (x1,y1)
slope for 2 points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)

points
(2,0)
(-6,4)
(0-4)/(2-(-6))=(-4)/(2+6)=-4/8=-1/2

m=-1/2

could be
y-4=-1/2(x+6)
or
y=-1/2(x-2)

6 0

2 years ago

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Amy gets a new kennel for her dog. A sketch of the kennel is shown here. If the roof is in the shape of a triangular prism (bott

rosijanka [135]

There is no image but i have seen a similar question which the answer to was 51 square feet

7 0

2 years ago

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