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Marizza181 [45]
2 years ago
14

Eileen is trying to test if the function f(x) = x2 + 2x + 5 is even, odd or neither. She produces the following work: f(– x) = (

–x)2 + 2(–x) + 5 = x2 – 2x + 5 What conclusion can she reach? f(x) is even f(x) is odd f(x) is neither f(x) is both even and odd
Mathematics
1 answer:
Elina [12.6K]2 years ago
8 0

Answer:

f(x) is neither even nor odd.

Step-by-step explanation:

For a function to be even f(x) = f(-x)  and  her results show that this is not the case.

For an odd function  -f(x) = f(-x) so we test this:

-f(x) =  -x^2 - 2x - 5 ; f(-x) =  x^2 - 2x + 5  -  so it is not odd.

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Answer:

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Step-by-step explanation:

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2 years ago
Three trigonometric functions for a given angle are shown below. cosecant theta = thirteen-twelfths; secant theta = Negative thi
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Answer:

(–5, 12) is the correct answer.

Step-by-step explanation:

We are given the following values:

cosec\theta = \dfrac{13}{12}\\sec\theta=-\dfrac{13}{5}\\cot\theta =-\dfrac{5}{12}

Now, we know the following identities:

sin \theta = \dfrac{1}{cosec\theta}\\cos \theta = \dfrac{1}{sec\theta}\\tan \theta = \dfrac{1}{cot\theta}

Now, the values are:

sin\theta = \dfrac{12}{13}\\cos\theta=-\dfrac{5}{13}\\tan\theta =-\dfrac{12}{5}

Sine value is positive and cos, tan values are negative.

It can be clearly observed that \theta is in 2nd quadrant.

2nd quadrant means, the value of x will be negative and y will be positive.

Let us have a look at the value of tan\theta:

tan\theta  = \dfrac{Perpendicular}{Base}\\OR\\tan\theta  = \dfrac{y-coordinate}{x-coordinate} = -\dfrac{12}{5}\\\therefore y = 12,\\x = -5

Please refer to the attached image for clear understanding and detailed explanation.

Hence, the correct answer is coordinate (x,y) is (–5, 12)

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