Question

7. Eva bought popcorn, candy and a drink at

Answer 1

Answer:

Step-by-step explanation:

let $p, $c and $d represents the costs of popcorn, candy and a drink respectively. If the popcorn was three times as  expensive as the candy then;

p = 3c.... 1

If the drink was  twice as expensive as the candy then d = 2c .... 2

If Eva spent a  total sum of $10.50 at the movies, the equation that represents the situation will be p + c + d = $10.50 .... 3

Substituting equation 1 and 2 into 3;

3c + c + 2c = $10.50

6c = $10.50

Hence the equation to represent the situation is 6c = $10.50 where c represents the cost of the candy.

b) To get c from the equation 6c = $10.50, we will simply divide both sides by the coefficient of c i.e 6 as shown

6c/6 = $10.50/6

c = $1.75

Hence the value of c is $1.75

c) The equation representing Eva's drink in terms of the candy is expressed as d = 2c

Substituting c = $1.75 into the equation will give;

d = 2(1.75)

d = 3.5

Hence the cost of Eva's drink is $3.50