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2 years ago

Categorize each molecule according to its hydrogen-bonding characteristics.a. CH3OCH3b. CH3CH2CH3c. CH3CH2NH2d. H2Oe. CH3OH

Chemistry

1 answer:

kkurt [141]2 years ago

8 0

Answer:

H2O > CH3OH > CH3CH2NH2 > CH3OCH3 > CH3CH2CH3

Explanation:

Hydrogen bonding exists in molecules in which hydrogen is bonded to a highly electronegative element such as fluorine, chlorine, oxygen, sulphur, nitrogen etc.

Water has the highest degree of hydrogen bonding among the listed substances hence its very high boiling point, stemming from intermolecular hydrogen bonding. CH3CH2NH2 has a lesser degree of hydrogen bonding because nitrogen is less electronegative than oxygen.

Alcohols show significant hydrogen bonding in solution, the same applied to amines. However, ethers do not form hydrogen bonds with each other but they can form hydrogen bonds with other molecules such as alcohols and amines. Alkanes do not form hydrogen bonds at all.

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Draw the structure of a compound with molecular formula c5h12 that exhibits only one kind of proton (all 12 protons are chemical

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This structure is called NeoPentane

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2 years ago

Why does silver iodide have a higher melting point than vanillin

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2 years ago

An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i

katovenus [111]

The answer is

The density (D) is quotient of mass (m) and volume (V):
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The unit is g/cm³

It is given:
m = 1.62 kg = 1620 g
V = 205 mL = 205 cm³
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Thus:
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2 years ago

Give the product for the reaction of 1-butene with methanol in the presence of acid. The mechanism is the same as the mechanism

Nuetrik [128]

Answer:

The final result is 2-methoxybutane.

Explanation:

1-butene has a carbon-carbon double bound between C1 and C2.

When it will react with methanol, in the presence of an acid, the result will be an ether.

C4H8 + CH3OH → C5H12O

An acid-catalyzed ether synthesis from alkenes is limited by carbocation stability.

In the first step, the double bound will disappear. The C2 atom will be a C+ atom, this becaus it has only 3 bounds and not 4.

This C+ -atom will atract the O- atom to form an ether. The CH3 of methanol will bind on the C3 atom, this is the most stable position.

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1-methoxybutane will not be formed, because it's less stable.

1-butanol will be formed when water is added to 1-butene. The mechanism has the same principle but not the same product.

1-ethoxybutane and 2-ethoxybutane have a structural formula of C6H14O, this will not be the final result.

The final result is 2-methoxybutane.

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2 years ago