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2 years ago

What is the spacing of the energy levels in the harmonic oscillator?

1 answer:

6 0

Answer: A diatomic molecule vibrates somewhat like two masses on a spring with a potential energy that depends upon the square of the displacement from equilibrium. But the energy levels are quantized at equally spaced values. This form of the frequency is the same as that for the classical simple harmonic oscillator.

Explanation:

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Yesinia read that certain perfume ingredients, called esters, would agitate bees. Because perfume formulas are secret, she decid

RUDIKE [14]

Answer:

Hypothesis: IF the perfumes contained Ester "X", THEN the bees would be agitated

Control group: The control group would be the group of bees that did not receive any perfume treatment

Experimental group: Bees that were exposed to the different perfumes

Independent variable: The type of perfumes

Dependent variable: the behavior of the bees

Explanation:

An hypothesis is a testable explanation or suggested solution to a problem that is subject to testing (for proving or disproving) via experimentation. The hypothesis of this experiment will be: IF the perfumes contained Ester "X", THEN the bees would be agitated

The control group of an experiment is the group that does not receive the experimental treatment or the group whose independent variable is not changed. In this case, there is no stated control group but control group of this particular experiment could be the BEES THAT WERE NOT EXPOSED TO ANY PERFUME.

The experimental group, as opposed to the control group, is the group that receives experimental treatment. In this case, it is the group of bees that were exposed to the different types of perfumes.

In an experiment, the variable that is deliberately changed by the experimenter is called the independent variable. The independent variable in this question is the TYPE OF PERFUME given to the bees.

The variable that responds to the changes made to the independent variable is called the dependent variable. The dependent variable, which is the measured variable, is THE BEHAVIOR OF THE BEES.

6 0

2 years ago

1. A chemist prepares hydrogen fluoride by means of the following reaction:

Natasha_Volkova [10]

Answer:

a) Theoretical Yield of HF = 5.64 grams

b) Percentage Yield = 39%

Explanation:

Reaction Given:

CaF2 + H2SO4 -> CaSO4 + 2HF

CaF2 = 11g

H2SO4 = Used in excess

HF = 2.2 g production = Actual Yield

So, Let's write down the molar masses:

Molar Mass of CaF2 = 78 g /mol

Molar Mass of HF = 20 g/mol

From the reaction, we can see the 1 mole of CaF2 gives the 2 moles of HF

i.e

a) Theoretical Yield of HF:

1 mole CaF2 = 2 moles HF

78 g CaF2 = 2 x 20 g of HF

78 g CaF2 = 40 g of HF

1 g CaF2 = 40g/78g of HF

And in the question it is given that chemist used 11 g of CaF2 so,

1 x 11 g of CaF2 = 11 x 40/78 g of HF

11 g of CaF2 = 440/78 g of HF

11 g of CaF2 = 5.64 g of HF

And this is the theoretical yield

Theoretical Yield of HF = 5.64 grams

b) Now, calculate the Percentage Yield of HF

Percentage Yield = Actual Yield /Theoretical Yield x 100

Percentage Yield = 2.2 g /5.64 g x 100

Percentage Yield = 39%

8 0

2 years ago

One litre of hydrogen at STP weight 0.09gm of 2 litre of gas at STP weight 2.880gm. Calculate the vapour density and molecular w

expeople1 [14]

Answer:

we know, at STP ( standard temperature and pressure).

we know, volume of 1 mole of gas = 22.4L

weight of 1 Litre of hydrogen gas = 0.09g

so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.

similarly,

weight of 2L of a gas = 2.88gm

so, weight of 22.4 L of the gas = 2.88 × 22.4/2 = 2.88 × 11.2 = 32.256g

hence, molecular weight of the gas = 32.256g

vapor density = molecular weight/2

= 32.256/2 = 16.128g

hence, vapor density of the gas is 16.128g.

Explanation:

4 0

1 year ago

Which of the following are part of kinetic-molecular theory? Check all that apply. The particles in a solid do not move. The par

djyliett [7]

2)The particles in a liquid are moving past one another constantly.
3)The particles in gas move freely in all directions.
4)The particles in a solid vibrate in a fixed position.
6)The particles in a gas have few attractions between them.
7)The particles in all states of matter are always moving.

7 0

2 years ago

Read 2 more answers

A relatively simple way of estimating profit is to consider the the difference between the cost (the total spent on materials an

Vika [28.1K]

Answer:

( $ 8,384 )

Explanation:

- From given information we know that 1 mol mCPHA provides the oxygens to 1 mol of propene, to make 1 mole of C3H6O so:

1 mol C3H6 + 1 mol mCPHA --> 1 mol C3H6O

( Mr = 42.08 g) ( Mr = 172.57 g) ( Mr = 58.08 g )

- For 1 kg equivalent equation by dividing the whole equation by the highest Molar Mass i.e of C3H6O, the result would be:

1 mol C3H6 + 1 mol mCPHA --> 1 mol C3H6O

( 42.08 / 58.08 ) ( 172.57 / 58.08 ) ( 1 )

= ( 0.72452 kg ) ( 2.9712 kg ) ( 1 kg )

- However note that the reaction gives only a 96% yield, we scale up the reactants to get that desired 1 kg of C3H6O:

(0.72452 kg ) (96/100) + (2.9712 kg) (96/100) --> 1 kg

= ( 0.75471 kg ) + ( 3.095 kg ) ---------------> 1 kg

- The costs for each component produced:

(0.75471 kg C3H6) ($10.97 per kg) = $8.279

(3.095 kg mCPHA) ($5.28 per kg) = $16.342

(0.75471 kg C3H6) / (0.0210 kg C3H6 / L dichloromethane) = 35.939

(35.939 Litres dichloromethane) ($2.12 per L) = $ 76.19

- The cost of waste disposal ($5.00 per kilogram of propene oxide) produced total cost, disregarding labor,energy, & facility costs:

$8.279 + $16.342 + $ 76.19 + $5.00 = $105.81 per kg C3H6O produced

- Profit: ($258.25 / kg C3H6O) - ($105.81 cost per kg) = $152.44 profit /kg

- Calculate the profit from producing 55.00kg of propene oxide:

(55.00kg) ($152.44 /kg) = $8,384.2 .. ( $ 8,384 )

6 0

2 years ago