Answer:
Mark the point of intersection S of circles R and P, and construct line QS.
Step-by-step explanation:
In the figure attached, the problem is shown. The construction of the tangent lines from point Q to circle P is almost done. The last step is to draw the lines that pass through point Q and the intersection of the circles.
There were 340,000 cattle placed on feed
How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?
Given the fraction of total cattle for 700 - 799 pounds is 2/5
Let x be the number of cattle between 700 - 799 pounds
We make a proportion using the fraction

Cross multiply it and solve for x
340000* 2 = 5x
680000 = 5x
Divide by 5 on both sides
So x= 136,000
There were 136,000 cattle between 700 and 799 pounds
You can start with the equation of
(1/6)x8+(1/8)x6+(1/12)x X=3
Multiply by common denominator of 24 to get
32+18+2x=72
Simplify it we get
50+2x=72
Eliminate using algebra (because it’s add 50 take away the 50 on both sides)
2x=22
Because it’s X2 divide by 2 on both sides
x=11
It will take 11 days
Answer:
(C)Determine the principal square root of both sides of the equation.
Step-by-step explanation:
Given: Isosceles right triangle XYZ (45°–45°–90° triangle)
To Prove: In a 45°–45°–90° triangle, the hypotenuse is
times the length of each leg.
Proof:

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, 
Since a=b in an isosceles triangle:

Therefore, the next step is to Determine the principal square root of both sides of the equation.
Answer:
x=9,-1 and 
Explanation:
we have been given with the quadratic equation 
we compare the given quadratic equation with general quadratic equation
general quadratic is 
from given quadratic equation a=1,b= -8,c= -9
substituting these values in the formula for discriminant 

Now, to find the value of x
Formula is 
Now, substituting the values we will get

And rewritting the given equation by shifting 9 to right hand side of the given equation and taking minus inside the bracket so as to convert it in the form of
