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Akimi4 [234]
2 years ago
3

Last night, the temperature fell from 0°F to Negative 13 and one-fifth°F in4 and two-fifths hours. Alan calculated the average t

emperature change per hour. Negative 13 and one-fifth divided by 4 and two-fifths = Negative StartFraction 66 over 5 EndFraction divided by StartFraction 22 over 5 EndFraction = Negative StartFraction 66 over 5 EndFraction (StartFraction 22 over 5 EndFraction) = Negative StartFraction 1,452 over 25 EndFraction Alan solved the problem, but when he checked the answer by estimating, it didn’t seem right. What error did he make?
Mathematics
2 answers:
astra-53 [7]2 years ago
8 0

Answer:

He did not use the correct reciprocal fraction.

Step-by-step explanation:

DedPeter [7]2 years ago
8 0

The answer is B:He did not use the correct reciprocal fraction.

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The <em><u>correct answer</u></em> is:

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Explanation:

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Answer:

y = -1/2 x

Step-by-step explanation:

Follow the directions "Complete the steps to write the equation of direct variation. Start with the equation of direct variation y = kx. Substitute in the given values for x and y to get . Solve for k to get . Write the direct variation equation with the value found for k."

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So the equation is y = -1/2(x).

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