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Karo-lina-s [1.5K]
2 years ago
4

A single galaxy is BEST described as containing A) millions of stars B) billions of stars C) thousands of stars D) trillions of

stars
Chemistry
2 answers:
IgorLugansk [536]2 years ago
7 0
A. millions of stars, or B. billions of stars because it would be the regular galaxy.
 
ipn [44]2 years ago
7 0

Answer:

B) billions of stars

Explanation:

A galaxy is a group of billions of stars. Galaxies are classified in three shapes:

1. elliptical

2. spiral

3. Irregular

Our home galaxy is Milky Way Galaxy which contains about a hundred billion stars. Thus, correct option is B.

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How many molecules of glucose are in 1 l of a 100 mm glucose solution?
Karolina [17]

Answer is: 6.022·10²² molecules of glucose.

c(glucose) = 100 mM.

c(glucose) = 100 · 10⁻³ mol/L.

c(glucose) = 0.1 mol/L; concentration of glucose solution.

V(glucose) = 1 L; volume of glucose solution.

n(glucose) = c(glucose) · V(glucose).

n(glucose) = 0.1 mol/L · 1 L.

n(glucose) = 0.1 mol; amount of substance.

N(glucose) = n(glucose) · Na (Avogadro constant).

N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.

N(glucose) = 6.022·10²².

6 0
2 years ago
Illustrate a model of a calcium atom including the number and position of protons neutrons and electrons in the atom
andrey2020 [161]

The model would look something like the image below.

There would be a <em>central nucleus</em> containing <em>20 protons</em> and <em>20 neutrons</em>.

Surrounding the nucleus would be four concentric rings (energy levels) containing <em>20 electron</em>s.

Going out from the nucleus, the number of electrons in each ring would

be <em>2, 8, 8, 2</em>.

8 0
2 years ago
A compound is known to contain only carbon, hydrogen, and oxygen. If the complete combustion of a 0.150-g sample of this compoun
Rzqust [24]

Answer: the empirical formula is C3H4O3

Explanation:Please see attachment for explanation

8 0
2 years ago
Read 2 more answers
A gold wire has a diameter of 1.00 mm. What length of this wire contains exactly 1.00 mol of gold? (density of Au = 17.0 g/cm3)
allochka39001 [22]

Answer:

The answer to your question is 7160 cm

Explanation:

Data

diameter = 1 mm

length = ?

amount of gold = 1 mol

density = 17 g/cm³

Process

1.- Get the atomic mass of gold

Atomic mass = 197 g

then, 197g ------------ 1 mol

2.- Calculate the volume of this wire

density = mass/volume

volume = mass/density

volume = 197/17

volume = 5.7 cm³

3.- Calculate the length of the wire

Volume = πr²h

solve for h

h = volume /πr²

radius = 0.05 cm

substitution

h = 5.7/(3.14 x 0.05²)

h = 5.7 / 0.0025

h = 7159.2 cm ≈ 7160 cm

8 0
2 years ago
Read 2 more answers
Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
ExtremeBDS [4]

Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

Depressioninfreezing point=K_{f}Xmolality

Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

moles=\frac{mass}{molarmass}=\frac{0.694}{154}=0.0045mol

massofcyclohexane=25g=0.025Kg

molarity=\frac{0.0045}{0.025}=0.18m

Depression in freezing point = 20X0.18=3.6^{0}C

The new freezing point = 6.5^{0}C-3.6^{0}C=2.9^{0}C

5 0
2 years ago
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