Answer:
369 students have taken a course in either calculus or discrete mathematics
Step-by-step explanation:
I am going to build the Venn's diagram of these values.
I am going to say that:
A is the number of students who have taken a course in calculus.
B is the number of students who have taken a course in discrete mathematics.
We have that:

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and
is the number of students who have taken a course in both calculus and discrete mathematics.
By the same logic, we have that:

188 who have taken courses in both calculus and discrete mathematics.
This means that 
212 who have taken a course in discrete mathematics
This means that 
345 students at a college who have taken a course in calculus
This means that 
How many students have taken a course in either calculus or discrete mathematics

369 students have taken a course in either calculus or discrete mathematics
Answer:
27 hours
Step-by-step explanation:
The regular hours are paid normally, 21/hr hence working for 40 hours, Michael earns 40*21=$840
To work x hours paid overtime as 1.5 of the normal rate, the rate would be $21*1.5=$31.5/hr
X hours multiplied by rate of $31.5/hr should be at least equal to $840
31.5x>=840
X>=840/31.5>=26.6667 hours and when rounded off
X is 27 hours
The figure shown below illustrates the problem.
The volume of the empty cone is
V₁ = (1/3) π r²h
The volume of the sphere is
V₂ = (4/3) π r³
Because the melted ice cream completely fills the cone, therefore
V₁ = V₂
(1/3) π r² h = (4/3) π r³
Divide each side by (1/3) π r².
h = 4r
Answer:
The height of the cone is 4 times greater than the radius f the cone.
The sound intensity of rustling leaves, y = 20 decibels
<u>Step-by-step explanation:</u>
y = 10logx
The sound intensity of rustling leaves is 100 times the reference intensity.
x = ratio of intensity of sound to reference to intensity
x = 100:1 or x = 100
y = 10 log(100) = 10 * 2 = 20 decibels
y = 20 decibels
<span>So
let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly
subtract this given equation. We need to convert the two given number into a
fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6
Now, we have 2 fractions with unlike denominator. In order to get a common
denominator, we have to find their least common factor.
=> <u>73</u> - <u>17 </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
</u> 8 6
8 x 6 6
x 8</span><span>
=> <u>438</u> – <u>136 </u> Now, we
have the same denominator, subtract</span><span>
48 48
=> <u>302 </u> or <u>151</u>
48 24
=> 6 <u>7</u>
24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.</span>