Answer:
Explanation:
Let the force required be F . It is applied at the top of the box . The box is likely to turn about a corner . Torque of this force about this corner
= F x 2
This torque will try to turn the box . On the other hand the weight which is acting at CM will create a torque about the same corner . This torque will try to prevent the box to turn around the corner.
This torque of weight
= 100 x 1
= 100 pound ft.
For equilibrium
Torque of F = torque of weight.
F x 2 = 100
F = 50 pounds .
Answer:
acceleration = -15.3g
Explanation:
given data
speed = 6.00 m/s.
thickness = 12
moves the entire = 12.0 cm
solution
we will use here equation that is
v² - u² = 2 × a × s ........................1
here v = 0 is the final velocity and u = 6.0 m/s is initial velocity and s= 0.12 m is the distance covered and a is the acceleration
so we put here value and get acceleration
a = 
a = 
a = -150 m/s² ( negative sign means it is a deceleration )
and
acceleration in units of g
a = 
a = -15.3 g
Conservation of linear momentum:
m*v inital = m*v final
0.06*0.7 + 0.03*0 = 0.06*(-0.2) + 0.03*v
(my algebra, or use ur calculator: 0.06*.07=0.042, etc ... or ur teacher may think you got some help)
0.06*(0.7+0.2)=0.03*v, v = 0.06*0.9/0.03=1.8 m/s
Answer 1.8 m/s (positive, to the right).
His average speed is (35m/45s) = 7/9 meters per second.
His average velocity is (30m W + 5m E) / (45s) = 25 m/s West .
The pressure needed in PSI = Pounds of force needed divided by the cylinder Area
The Cylinder rod Area is 21.19 sq inches
Thus, the pressure= 6800/21.19
= 320.91 PSI
