Answer:
A) x = (-32, - 65)
B) 72 miles
C) 26°
Explanation:
A) If we consider Ruth's home as origin, then at wards home, position vector is;
x1 = 100i + 50j
This is because the question said 100miles east of her which is on the positive x-axis and 50 miles north which is on the positive y-axis.
At Ruth's home, position vector will be;
x2 = 68i - 15j
Because she is moving closer to the positive x-axis in 60 miles after which she also flied east in 8 miles. Also, she went south in 15 miles which is down the negative y-axis.
Thus, displacement vector is;
x = x2 - x1 = 68i - 15j - (100i + 50j)
x = 68i - 15j - 100i - 50j
x = -32i - 65j
In component form, we have;
x = (-32, - 65)
B) Magnitude of wards displacement vector;
|x| = √((-32)² + (-65²))
|x| = √(1024 + 4225)
|x| = √5249
|x| ≈ 72 miles
C) direction of Ward's displacement vector, measured clockwise from the negative y axis is;
θ = tan^(-1) (-32/-65)
θ = tan^(-1) 0.4923
θ = 26°