Reducing waste benefits your shop by cutting down on pollution and _________

CHALLENGE ACTIVITY 2.8.1: Using constants in expressions. The cost to ship a package is a flat fee of 75 cents plus 25 cents per

mihalych1998 [28]

Answer:

Weight(lb): 10

Flat fee(cents): 75

Cents per pound: 25

Shipping cost(cents): 325

Explanation:

we run this as a jave programming language

import java.util.Scanner;

public class Shipping Calculator {

public static void main (String [] args) {

int shipWeightPounds = 10;

int shipCostCents = 0;

final int FLAT_FEE_CENTS = 75;

final int CENTS_PER_POUND = 25;

shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPound

/* look up the solutioin above */

System.out.println("Weight(lb): " + shipWeightPounds);

System.out.println("Flat fee(cents): " + FLAT_FEE_CENTS);

System.out.println("Cents per pound: " + CENTS_PER_POUND);

System.out.println("Shipping cost(cents): " + shipCostCents);

}

7 0

2 years ago

Small droplets of carbon tetrachloride at 68 °F are formed with a spray nozzle. If the average diameter of the droplets is 200 u

Licemer1 [7]

Answer:

the difference in pressure between the inside and outside of the droplets is 538 Pa

Explanation:

given data

temperature = 68 °F

average diameter = 200 µm

to find out

what is the difference in pressure between the inside and outside of the droplets

solution

we know here surface tension of carbon tetra chloride at 68 °F is get from table 1.6 physical properties of liquid that is

σ = 2.69 × $10^{-2}$ N/m

so average radius = $\frac{diameter}{2}$ = 100 µm = 100 × $10^{-6}$ m

now here we know relation between pressure difference and surface tension

so we can derive difference pressure as

2π×σ×r = Δp×π×r² .....................1

here r is radius and Δp pressure difference and σ surface tension

Δp = $\frac{2 \sigma }{r}$

put here value

Δp = $\frac{2*2.69*10^{-2}}{100*10^{-6}}$

Δp = 538

so the difference in pressure between the inside and outside of the droplets is 538 Pa

7 0

2 years ago

Steam enters a turbine operating at steady state at 1 MPa, 200 °C and exits at 40 °C with a quality of 83%. Stray heat transfer

Andrei [34K]

Answer:

(a) Work out put=692.83 $\frac{KJ}{Kg}$

(b) Change in specific entropy=0.0044 $\frac{KJ}{Kg-K}$

Explanation:

Properties of steam at 1 MPa and 200°C

$h_1=2827.4\frac{KJ}{Kg},s_1=6.69\frac{KJ}{Kg-K}$

We know that if we know only one property in side the dome then we will find the other property by using steam property table.

Given that dryness or quality of steam at the exit of turbine is 0.83 and temperature T=40°C.So from steam table we can find pressure corresponding to saturation temperature 40°C.

Properties of saturated steam at 40°C

$h_f= 167.5\frac{KJ}{Kg} ,h_g= 2537.4\frac{KJ}{Kg}$

$s_f= 0.57\frac{KJ}{Kg-K} ,s_g= 8.25\frac{KJ}{Kg-K}$

So the enthalpy of steam at the exit of turbine

$h_2=h_f+x(h_g-h_f)\frac{KJ}{Kg}$

$h_2=167.5+0.83(2537.4-167.5)\frac{KJ}{Kg}$

$h_2=2134.57\frac{KJ}{Kg}$

$s_2=s_f+x(s_g-s_f)\frac{KJ}{Kg-K}$

$s_2=0.57+0.83(8.25-0.57)\frac{KJ}{Kg-K}$

$s_2=6.6944\frac{KJ}{Kg-K}$

(a)

Work out put = $h_1-h_2$

=2827.4-2134.57 $\frac{KJ}{Kg}$

Work out put =692.83 $\frac{KJ}{Kg}$

(b) Change in specific entropy

$s_2-s_1=6.6944-6.69\frac{KJ}{Kg-K}$

Change in specific entropy =0.0044 $\frac{KJ}{Kg-K}$

3 0

2 years ago

g The function below takes a single string parameter: sentence. Complete the function to return everything but the middle 10 cha

ale4655 [162]

Answer:

def processString(sentence):
middle = len(sentence) // 2
output = sentence[0: middle - 5] + sentence[middle+5:]
return output
print(processString("I have a dream"))

Explanation:

Create a function processString that take sentence as input paratemer (Line 1).

Next create a variable middle to hold the value of middle index of sentence string (Line 2)

Build the output string by slicing the input sentence from first character to character middle - 5th and from middle + 5th till the end of the string (Line 3).

Test the function using a sample sentence and we shall get the output "I am"

4 0

2 years ago

a. (24 points) Describe the microstructure present in a 10110 steel after each step in each of the following heat treatments (no

Mrac [35]

Answer:

Explanation:

Please check the below file for the attached file

6 0

2 years ago

Reducing waste benefits your shop by cutting down on pollution and __________.