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lina2011 [118]
2 years ago
4

Anita places three cubes on a table. One cube is lead, the second is ice, and

Chemistry
2 answers:
nignag [31]2 years ago
5 0
 The answer is C. VOLUME.
Fed [463]2 years ago
4 0
The correct answer is :C the same volume
You might be interested in
What mass of carbon dioxide (co2) can be produced from 86.17 grams of c6h14 and excess oxygen?
charle [14.2K]
2C6H14 + 13O2 ---> 6CO2 +14H2O

M(C6H14)=12.011*6 +1.008*14 ≈ 86.17 g/mol

86.17 g C6H14 is 1 mole.

                             2C6H14 + 13O2 ---> 6CO2 +14H2O
from reaction        2 mol                         6 mol
from the problem  1 mol                         3 mol

M(CO2)= 12.011 + 2*15.999= 44.009 g/mol
3 mol CO2*44.009 g/1 mol CO2 ≈ 132.0 g CO2
Answer : 132.0 g CO2


3 0
2 years ago
(g) On the graph in part (d) , carefully draw a curve that shows the results of the second titration, in which the student titra
atroni [7]

Answer:

Here's what I get  

Explanation:

(g) Titration curves

I can't draw two curves on the same graph, but I can draw two separate curves for you.  

The graph in part (d) had an equivalence point at 20 mL.

In the second titration, the NaOH was twice as concentrated, so the volume to equivalence point would be half as much — 10 mL.

The two titration curves are below.

(h) Evidence of reaction

HCl and NaOH are both colourless.

They don't  evolve a gas or form a precipitate when they react.

The student probably noticed that the Erlenmeyer flask warmed up — a sign of a chemical change.

4 0
2 years ago
A boy lifts a 30N dragon 2 meters above the ground. How much work did the boy do on the dragon?
pychu [463]

Answer:

Work= Fs

Work 30x2

Work 60 J

Explanation:

A lot of work

3 0
2 years ago
PLEASE HELP!!!!!!
Bas_tet [7]
The reaction that is a double displacement reaction is the final one. Between Pb(NO3)2 and HCl.
6 0
2 years ago
Read 2 more answers
How would each of the following procedural errors affect the results to be expected in this experiment? Give your reasoning in e
Digiron [165]

Answer:

a) if the liquid is not vaporized completely, then the condensed vapor in the flask contains the air which is initially occupied before the liquid is heated. When calculating the molar mass of the vapor the moles of air which are initially present are not excluded, so that the molar mass of the vapor would be an increase in value.

b) While weighing the condensed vapor, the flask should be dried. If the weighing flask is not dried then the water which is layered on the surface of the flask is also added to the mass of the vapor. Therefore, the mass of the vapor that is calculated would be increase.

c) When condensing the vapor, the stopper should not be removed from the flask, because the vapor will escape from the flask and a small amount of vapor will condense in the flask. Therefore, the mass of the condensed vapor would be In small value.

d) If all the liquid is vaporized, when the flask is removed before the vapor had reached the temperature of boiling water, then the boiling

temperature of that liquid would be lower than that of the boiling temperature of the water.Therefore, the liquid may have more volatility.

7 0
2 years ago
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