All categories

2 years ago

A dog runs 3 miles and 4 miles west in 6 hours. What’s the dogs total distance and displacement ?

Physics

1 answer:

Inga [223]2 years ago

6 0

Complete question:

A dog runs 3 miles east and 4 miles west in 6 hours. What’s the dogs total distance and displacement ?

Answer:

The total distance covered by the dog is 7 miles

The displacement of the dog is 1 mile west

Explanation:

Given;

initial position of the dog = 3 miles east

final position of the dog = 4 miles west

time of motion, t = 6 hours

The total distance covered by the dog is given as;

Total distance = 3 miles + 4 miles = 7 miles

The displacement of the dog is given as;

displacement = final position of the dog - initial position of the dog

displacement = 4 miles west - 3 miles east = 1 mile west

You might be interested in

A 10 kg package is delivered to your house. Use one complete sentence to describe an example of how work is done on the package

Mamont248 [21]

Answer:

Hey :)

Explanation:

Work is a net force applied through a distance in order to displace an object, commonly abbreviated as W. A net force is the sum of all forces acting on an object. Work is mass times acceleration and distance so to find out the work you simply calculate the acceleration of the box being brought in. Next find the distance it was carried to get in the house. Then find out the mas of the box and finally multiply those sums together to get the amount of work put in to bring the package inside.

hope this helps :) xo

8 0

2 years ago

An electron moving parallel to a uniform electric field increases its speed from 2.0 × 107 m/s to 4.0 × 107 m/s over a distance

jeka94

Answer:

$1.8\times 105 N/C$

Explanation:

We are given that

$u=2\times 10^7 m/s$

$v=4\times 10^7 m/s$

d=1.9 cm= $\frac{1.9}{100}=0.019 m$

Using 1m=100 cm

We have to find the electric field strength.

$v^2-u^2=2as$

Using the formula

$(4\times 10^7)^2-(2\times 10^7)^2=2a(0.019)$

$16\times 10^{14}-4\times 10^{14}=0.038a$

$0.038a=12\times 10^{14}$

$a=\frac{12}{0.038}\times 10^{14}=3.16\times 10^{16}m/s^2$

$q=1.6\times 10^{-19} C$

Mass of electron,m $=9.1\times 10^{-31} kg$

$E=\frac{ma}{q}$

Substitute the values

$E=\frac{9.1\times 10^{-31}\times 3.16\times 10^{16}}{1.6\times 10^{-19}}$

$E=1.8\times 105 N/C$

7 0

2 years ago

An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction

DiKsa [7]

Refer to the diagram shown below.

The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²

After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
= m(u/2)²
= (1/4)mu²
= (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer: 1/2

5 0

2 years ago

Read 2 more answers

Equal masses of granite, iron, copper, and lead are placed in sunlight. Based on specific heat, which material will warm up the

bogdanovich [222]

Answer is lead, lead will heat up the fastest as it has the highest specific heat amongst the choices. The higher the specific heat of the substance the easier it is for that substance temperature to change for every mole of substance with respect to a degree in kelvin.

5 0

2 years ago

Read 2 more answers

Recall that the essential matrix E describing the stereo geometry of two calibrated cameras is a function only of the relative r

Mashcka [7]

Answer:

The essential matrix in this case is given by

$E=[T_{x}]R=\left[\begin{array}{ccc}0&0&0\\0&0&d\\0&-d&0\end{array}\right]$