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dimulka [17.4K]
2 years ago
15

Write a hypothesis for Section 2 of the lab, which is about the effect of the angle of insolation on the amount of heat a materi

al absorbs. Use the format "if . . . then . . . because . . ." and be sure to answer this part of the lesson question: "What factors influence the absorption of sunlight at Earth's surface?"
Chemistry
1 answer:
m_a_m_a [10]2 years ago
5 0

Answer:

If the angle of insolation is higher, then the temperature of the soil will be higher because it will receive more direct light.

Explanation:

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What would the % p, on the npk ratio, be reported as for a 100g sample containing 7.5g of phosphorous?
kati45 [8]
When the concentration is expressed in percentage, you simply have to divide the amount of substance to the total amount of the mixture, then multiply it by 100. In this case, when you want to find the percentage of P in the sample, the solution is as follows:

%P = 7.5 g/100 g * 100 =<em> 7.5%</em>
6 0
2 years ago
Read 2 more answers
Now consider the example of a positive charge q moving in the xy plane with velocity v⃗ =vcos(θ)i^+vsin(θ)j^ (i.e., with magnitu
Hoochie [10]
<span>The magnetic force is in the positive y direction. This can be found using the "right hand rule" of forces.</span>
5 0
1 year ago
A solution is prepared by dissolving 0.60 g of nicotine (a nonelectrolyte) in water to make 12 mL of solution. The osmotic press
Mariulka [41]

Answer:

Molecular weight of nicotine is 162 g/mol

Explanation:

Osmotic pressure (\pi) for nonelectrolyte is expressed as-

                                    \pi =CRT

where C is molarity of solution, R is gas constant and T is temperature in Kelvin scale.

If molecular weight of nicotine is W g/mol then number of moles of nicotine present in solution is equal to \frac{0.60}{W} moles

So, molarity (C) of solution = \frac{0.60\times 1000}{W\times 12}M

R is equal to 0.082 L.atm/(mol.K), T is 298 K and \pi) is 7.55 atm

So, 7.55=(\frac{0.60\times 1000}{W\times 12})\times (0.082)\times (298)

or, W = 162

So molecular weight of nicotine is 162 g/mol

3 0
2 years ago
What is the specific heat of an unknown metal if 1.67 kcal of energy are required to raise the temperature of 79.2 g sample of t
sergij07 [2.7K]

Answer:

The answer to your question is       C = 0.000333 kcal/g°C

or  C = 0.333 cal/g°C

Explanation:

Data

 Q = 1.67 kcal

 mass = 79.2 g

 ΔT = 63.3°C

Formula

 Q = mCΔT

Solve for C

 C = Q/mΔT

Substitution

  C = 1.67/(79.2 x 63.3)

Simplification

   C = 1.67 / 5013.4

Result

    C = 0.000333 kcal/g°C

or  C = 0.333 cal/g°C

4 0
1 year ago
Read 2 more answers
You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out
mina [271]

Answer:

The diameter of the oil molecule is 4.4674\times 10^{-8} cm .

Explanation:

Mass of the oil drop = m=9.00\times 10^{-7} kg

Density of the oil drop = d=918 kg/m^3

Volume of the oil drop: v

d=\frac{m}{v}

v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = 4\pi r^2

a=4\times 3.14\times (0.418 m)^2=2.1945 m^2

Volume of the oil drop = v = Area × thickness

\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x

x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm

The thickness of the oil drop is 4.4674\times 10^{-8} cm and so is the diameter of the molecule.

6 0
1 year ago
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