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Andru [333]
2 years ago
13

Carmen is designing an experiment to determine the reactivity of certain elements on the Periodic Table. Which elements will mos

t likely have similar reactive properties? * 10 points Fluorine (F) and Neon (Ne) Hydrogen (H) and Helium (He) Sodium (Na) and Potassium (K) Aluminum (Al) and Chlorine (Cl)
Chemistry
1 answer:
Vinvika [58]2 years ago
5 0

Answer:

Option C: sodium and potassium

Explanation:

Elements in same group having same properties. In given option Only C is the correct option because sodium and potassium are present in same group i.e, group 1 and thus shows similar reactive properties. Bothe are alkali metal and have one valance electron. These are very reactive and can not found in free state in nature but present in compounds.

They react with halogens and form salts.

2Na + Cl₂  →  2NaCl

2K + Cl₂  →  2KCl

All other options are incorrect because,

Option A = Fluorine and neon

Both are present in different group. Fluorine is present in group 17 and neon in group 18 thus their reactivity is not similar.

Option B = Hydrogen and helium

Both are present in different group. Hydrogen is present in group 1 and helium in group 18 thus their reactivity is not similar.

Option D: Aluminum and chlorine

Both are present in different group. Aluminum is present in group 13 and chlorine in group 17 thus their reactivity is not similar.

All these three options are incorrect.

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Answer:

The answer to your question is below:

Explanation:

Having exactly the same data as the previous experiment I think that having the same data as the previous experiment is extremely important but not the most important, for me is the second most important.

Using the same procedure and variables as the previous experiment For me, this is the most importan thing when a scientist is designing an experiment, because if he or she follow exactly the same procedure and variables, then the results will be very close.

Conducting an experiment similar to the previous experiment  This characteristic is important but not the most important.

Using the same laboratory that was used in the previous experiment It is not important the laboratory, if the procedure and variables are the same, your experiment must give the same results in whatever laboratory.

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When 24 mol of methanol and 15 mol of oxygen combine in the combustion reaction, 2 ch3oh(
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The balanced equation for combustion is as follows;
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If methanol is the limiting reactant,
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2 years ago
How many moles of FeS2 are required to produce 32g of SO2?
nirvana33 [79]

Answer:

<u>So, the right answer is</u>

No. of moles of FeS₂ = 0.25 mole

Explanation:

From the balanced

4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

it is clear that 4 mol  FeS₂ react with O₂ to give Fe₂O₃ and 8 mol of SO₂

First, we have to convert mass of SO₂ into No. of moles as following:

SO₂ has molar mass = 64 g/mol

No. of moles of SO₂ = (mass / molar mass) = (32 g / 64 g/mol) = 0.5 mol

we know that  

4 mol  FeS₂  gives→ 8 mol of SO₂

1 mol  FeS₂  gives→ 2 mol of SO₂

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7 0
2 years ago
Hydrogen, a potential future fuel, can be produced from carbon (from coal) and steam by the following reaction: C(s)+2H2O(g)→2H2
madam [21]

The question is incomplete , complete question is:

Hydrogen, a potential future fuel, can be produced from carbon (from coal) and steam by the following reaction:

C(s)+ 2 H_2O(g)\rightarrow 2H_2(g)+CO_2(g).\Delta H=?

Note that the average bond energy for the breaking of a bond in CO2 is 799 kJ/mol. Use average bond energies to calculate ΔH of reaction for this reaction.

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The ΔH of the reaction is -626 kJ/mol.

Explanation:

C(s)+ 2 H_2O(g)\rightarrow 2H_2(g)+CO_2(g).\Delta H=?

We are given with:

\Delta H_{H-O}=459 kJ/mol

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\Delta H_{C=O}=799 kJ/mol

ΔH =  (Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)

\Delta H=(4\times \Delta H_{O-H})-(2\times \Delta H_{H-H}+2\times\Delta H_{C=O})

=(4\times 459 kJ/mol)-(2\times 432 kJ/mol+2\times 799 kJ/mol

\Delta H=-626 kJ/mol

The ΔH of the reaction is -626 kJ/mol.

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