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BartSMP [9]
2 years ago
12

Two samples of matter differ in temperature by 20°C. What is the difference in temperature of these two samples using the Kelvin

scale?
The difference is .......... kelvin



Hiii
Help me pls.
Chemistry
1 answer:
anyanavicka [17]2 years ago
5 0

Answer:

The difference is 293.15 Kelvin.

Explanation:

Given data:

Temperature difference of matter = 20°C

Temperature difference of matter in kelvin = ?

Solution;

Formula:

0°C +273.15

now we will put the values instead of 0.

20°C + 273.15 = 293.15 K

Thus, the temperature difference between two sample is 293.15 K.

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The values used in the scale of pH and pOH are derived from a system designed by ______. Gordonsen Sorenson Curie Dalton
yaroslaw [1]

Sorenson

Explanation:

The values used in the scale of pH and pOH are derived from a system designed by Sorenson. Søren Peter Lauritz Sørensen, a Danish chemist introduced the system of pH and pOH for describing the alkalinity and acidity of substances.

  • The pH and pOH scale is logarithmic scale that ranks the acidity and bascity of compounds.
  • pH is the negative logarithm of the concentration of  hydrogen/hydroxonium ions in solution i.e

              pH = -log₁₀{H⁺]

  • pOH is the negative log of the concentration of the hydroxyl ions in a solution i.e

             pOH = -log₁₀{OH⁻]

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3 0
2 years ago
Sodium acetate spontaneously crystallizes out of a supersaturated solution upon standing or upon the addition of a seed crystal.
AlekseyPX

Answer:

Option (c) is correct.

Explanation:

According to 2nd law of thermodynamics, every spontaneous process is associated with increase in entropy (\Delta S>0).

As sodium acetate crystallizes out spontaneously therefore it is associated with \Delta S>0.

During crystallization, bond formation takes place which results evolution of heat. In other words, crystallization phenomenon is exothermic (\Delta H).

So, the given crystallization process renders the following thermodynamic quantities- \Delta S>0 J/K and \Delta H J

Option (c) is correct.

6 0
2 years ago
A copper rod that has a mass of 200.0 g has an initial temperature of 20.0°C and is heated to 40.0°C. If 1,540 J of heat are nee
Romashka [77]

Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC(T2-T1)</span>

1540 = 200.0 (C)(40 - 20)

<span> <span>C = 0.385 J / g C</span></span>

<span><span>
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<span><span>Hope this answers the question. Have a nice day.</span></span>

8 0
2 years ago
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Suppose you are studying the K sp of K C l O 3 , which has a molar mass of 122.5 g/mol, at multiple temperatures. You dissolve 4
Ghella [55]

Answer:

The K sp Value is  K_{sp}=7.40

Explanation:

From the question we are told that

   The of KClO_3 is = 122.5 g/ mol

    The mass of KClO_3 dissolved is m_s = 4.0g

    The volume of solution is  V_s = 12mL = 12*10^{-3}L

The number of moles of KClO_3 is mathematically evaluated as

           No \ of  \ moles  \ = \frac{mass }{Molar \ mass}

Substituting values

                                  = \frac{4}{122.5}

                                  =0.0327\ moles

Generally concentration is mathematically represented as

         concentration = \frac{No \ of \ moles}{volume }

For KClO_3        

               Z= \frac{0.0327}{12*10^{-3}}

                              =2.72 \ mol/L

The dissociation reaction of KClO_3  is

         KClO_3 \ ----> K^{+}_{(aq)} + ClO_3^-_{(aq)}

The solubility product constant is mathematically represented as

                   K_{sp} = \frac{concentration of ionic product }{concentration of ionic reactant }

Since there is no ionic reactant we have

                  K_{sp} = [k^+] [ClO_3^-]

                          = Z^2

                          = 2.72^2

                          K_{sp}=7.40

                         

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