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insens350 [35]
1 year ago
13

Recording station x has determined that the epicenter of a recent earthquake was 250 km away. no information is available yet fr

om any other recording stations. what can you conclude about the location of the epicenter?
Chemistry
2 answers:
KatRina [158]1 year ago
7 0
The epicenter was located somewhere on a circle centered at Recording station X, with a radius of 250 km.<span>
</span>
zhenek [66]1 year ago
3 0

Answer:

In seismology, the epicenter refers to the point on the surface of the Earth directly above the focus or a hypocenter, that is, the point where an underground explosion or an earthquake originates. In the given case, the recording station has demonstrated that the epicenter of the recent earthquake was 250 kilometers away, this shows that epicenter was situated somewhere on a circle centered at the recording station within a radius of 250 kilometers.

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Why is it important to have regular supervision of the weight and measurements in the market
Sergio [31]

Answer:

Supervision of weights and measures promotes accurate measurements of goods and services to ensure that everybody gets a fair trade in the marketplace. Not so coincidentally it also is a deterrent to ensure that traders are being honest in their trade practises.

Explanation:

4 0
2 years ago
A sample of neon gas at a pressure of 1.08 atm fills a flask with a volume of 250 mL at a temperature of 24.0 °C. If the gas is
musickatia [10]

Answer:

124.91mL

Explanation:

Given parameters:

P₁  = 1.08atm

V₁  = 250mL

T₁  = 24°C

P₂  = 2.25atm

T₂  = 37.2°C

V₂  = ?

Solution:

To solve this problem, we are going to apply the combined gas law;

              \frac{P_{1} V_{1} }{T_{1} }   =  \frac{P_{2} V_{2} }{T_{2} }

P, V and T represents pressure, volume and temperature

1 and 2 delineates initial and final states

Convert the temperature to kelvin;

        T₁  = 24°C,  T₁   = 24 + 273 = 297K

        T₂  = 37.2°C , T₂  = 37.2 + 273  = 310.2K

Input the variables and solve for V₂

        \frac{1.08 x 250}{298} = \frac{2.25 x V_{2} }{310.2}

           V₂ = 124.91mL

6 0
2 years ago
Janine is trying to separate some ethanol from water. Which method should she use does anyone know this
GuDViN [60]

To separate some ethanol from water, Jane needs to use the method of simple distillation.

Simple distillation is a separation method in which two liquids can be separated from each other based on differences in boiling point.

Since water has a higher boiling point than ethanol, ethanol is collected first as the distillation proceeds.

Learn more:  brainly.com/question/2193327

5 0
2 years ago
¿Cuántos moles de aluminio (AI) se necesitan para formar 3,7 mol de Al2O3? 4Al(s) + 302 (g) -&gt; 2A1203 (s) ​
tatuchka [14]

Answer:

3.7 mol Al2O3 x 4 mol Al = 7.4 mol Al 2 mol Al2O3

Explanation:

8 0
2 years ago
Acetone has a boiling point of 56.5 celcius. How many grams of the acetone vapor would occupy the 250 mL Erlenmeyer flask at 57
vodomira [7]

Answer:

0.515 g

Explanation:

<em>Acetone (C₃H₆O) has a boiling point of 56.5 °C. How many grams of the acetone vapor would occupy the 250 mL Erlenmeyer flask at 57 °C and 730 mmHg?</em>

<em />

Step 1: Given data

Temperature (T): 57°C

Pressure (P): 730 mmHg

Volume (V): 250 mL

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15 = 57°C + 273.15 = 330 K

Step 3: Convert "P" to atm

We will use the conversion factor 1 atm = 760 mmHg.

730 mmHg × (1 atm/760 mmHg) = 0.961 atm

Step 4: Convert "V" to L

We will use the conversion factor 1 L = 1,000 mL.

250 mL × (1 L/1,000 mL) = 0.250 L

Step 5: Calculate the moles (n) of acetone

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.961 atm × 0.250 L/(0.0821 atm.L/mol.K) × 330 K

n = 8.87 × 10⁻³ mol

Step 6: Calculate the mass corresponding to 8.87 × 10⁻³ moles of acetone

The molar mass of acetone is 58.08 g/mol.

8.87 × 10⁻³ mol × 58.08 g/mol = 0.515 g

8 0
1 year ago
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