Question

Consider a capacitor made of two rectangular metal plates of length and width , with a very small gap between the plates. There is a charge on one plate and a charge on the other. Assume that the electric field is nearly uniform throughout the gap region and negligibly small outside. Calculate the attractive force that one plate exerts on the other. Remember that one of the plates doesn't exert a net force on itself. (Enter the magnitude. Use any variable or symbol stated above along with the following as necessary: .)

Answer 1

This question is incomplete, the complete question is;

Consider a capacitor made of two rectangular metal plates of length L and width W, with a very small gap s between the plates. There is a charge +Q on one plate and a charge −Q on the other. Assume that the electric field is nearly uniform throughout the gap region and negligibly small outside.

Calculate the attractive force that one plate exerts on the other.

Remember that one of the plates doesn't exert a net force on itself. (Enter the magnitude. Use any variable or symbol stated above along with the following as necessary : ε0.)

Answer:

the attractive force F that one plate exerts on the other is Q² / 2ε0⊥ω

Explanation:

Given the information in the questioN;

Electric field by one plate at the pos of other plate is expressed as;

E₊ = r / 2ε0 = Q/2ε0A

SO force on the other plate

F = /QE₊ / = Q² / 2ε0A

F = Q² / 2ε0⊥ω

Therefore the attractive force that one plate exerts on the other is F = Q² / 2ε0⊥ω