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Ede4ka [16]
2 years ago
11

In science class, Blaine’s teacher puts one glow stick in a cup of hot water and another glow stick in a cup of cold water. She

asks the students to think about how the temperature of the water will affect the chemical reaction that occurs inside the glow stick once it is bent and starts to glow.
Which glow stick will be brighter once it is bent? Explain your answer.
Chemistry
2 answers:
timofeeve [1]2 years ago
3 0

Answer:

The glow stick in hot water will be brighter

Explanation:

The glow stick in hot water will be brighter than the glow stick in cold water because the heat from the hot water will cause the molecules in the glow stick to move faster. The faster the molecules move in the glow stick, the sooner and brighter the reaction will be. The cold water will cause molecules to move slowly and it will take longer for the reaction to occur, which will also make it less bright.

Maurinko [17]2 years ago
3 0

Answer:

The glow stick that was in the cup of hot water will be brighter once it is bent. The production of more light is evidence that the chemical reaction in the glow stick is happening faster. The reaction happens faster, because increasing the temperature increases the rate of a chemical reaction.

Explanation:

Just took assignment

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A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6
JulijaS [17]
Specific heat is the amount of heat absorb or released by a substance to change the temperature to one degree Celsius. To determine the specific heat, we use the expression for the heat absorbed by the system. Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:
Heat = mC(T2-T1)
By substituting the given values, we can calculate for C which is the specific heat of the material.
2510 J = .158 kg ( 1000 g / 1 kg) (C) ( 61.0 - 32.0 °C)C = 0.5478 J / g °C
8 0
1 year ago
Read 2 more answers
Consider the reaction H2(g) + Cl2(g) → 2HCl(g)ΔH = −184.6 kJ / mol If 2.00 moles of H2 react with 2.00 moles of Cl2 to form HCl,
zalisa [80]

Answer:

ΔU=-369.2 kJ/mol.

Explanation:

We start from the equation:

Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.

If Δ(PV) were calculated by ideal gas law,

PV=nRT

Δ(PV)=RTΔn.

Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.

So, for this case, ΔH=ΔU.

The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

2 reactant moles*\frac{-184.6kJ}{mol}

ΔU=-369.2 kJ/mol.

4 0
2 years ago
Mori walks into a restaurant. Upon smelling the food cooking, her mouth starts to water. Which system in the body detected the i
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Answer:

Digestive system

6 0
2 years ago
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Carbonic acid, H2CO3, has two acidic hydrogens. A solution containing an unknown concentration of carbonic acid is titrated with
stepan [7]

Answer:

1) Net ionic equation :

2H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)

2) 0.765 M is  the molarity of the carbonic acid solution.

Explanation:

1) In aqueous carbonic acid , carbonate ions and hydrogen ion is present.:

H_2CO_3(aq)\rightarrow 2H^+(aq)+CO_3^{2-}(aq) ..[1]

In aqueous potassium hydroxide , potassium ions and hydroxide ion is present.:

KOH(aq)\rightarrow K^+(aq)+OH^{-}(aq) ..[2]

In aqueous potassium carbonate , potassium ions and carbonate ion is present.:

K_2CO_3(aq)\rightarrow 2K^+(aq)+CO_3^{2-}(aq) ..[3]

H_2CO_3(aq)+2KOH(aq)\rightarrow K_2CO_3(aq)+2H_2O(l)

From one:[1] ,[2] and [3]:

2H^+(aq)+CO_3^{2-}(aq)+2K^+(aq)+2OH^{-}(aq)\rightarrow 2K^+(aq)+CO_3^{2-}(aq)+H_2O(l)

Cancelling common ions on both sides to get net ionic equation :

2H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)

2)

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2CO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=?\\V_1=50.0 mL\\n_2=1\\M_2=3.840 M\\V_2=20.0 mL

Putting values in above equation, we get:

M_1=\frac{1\times 3.840 M\times 20.0 mL}{2\times 50.2 mL}=0.765 M

0.765 M is  the molarity of the carbonic acid solution.

6 0
2 years ago
HCN forms when synthetic fibers containing Orlon® or Acrilan® burn. Acrilan® has an empirical formula of CH2CHCN, so HCN is 50.9
hichkok12 [17]

Answer:

676 g

Explanation:

First, let's calculate the area of the rug: 3.70x4.20 = 15.54 m². Knowing that 1 yard has 0.9144 m, so

1 yd² = (0.9144 m)² = 0.8361 m²

So, there is 30.0 oz in 0.8361 m²

30.0 oz-----------------0.8361 m²

x           -----------------15.54 m²

By a simple direct three rule:

0.8361x = 466.2

x = 557.6 oz of Acrilan in the rug

1 oz =  28.35 grams, so 557.6 oz = 15807.96 g

The potencial of HCN is 50.9% of this mass, so: 0.509x15807.96 = 8046.25 g.

But only 42.0% of the rug is burned, so the potencial of HCN is 42.0% of  8046.25: 0.42x 8046.25 = 3379.42 g.

And the yield is only 20.%, so the mass formed of HCN is:

0.20x3379.42 = 676 g

5 0
1 year ago
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