Answer:check explanation
Explanation:
No diagram is given above but to determine the value of melting point we need to understand the fact that NaCl has a lower melting point than MgS.
Reasons are; (1) sodium ion (+1) in the first group of the periodic table is characterized by its softness and low melting point and, (2). Is that it has a lower melting point than MgS because the COULUMBIC ATTRACTIONS between its singly charged sodium ions(+1) and the chlorine ions(-1) are weaker than those between the ions in MgS.
Answer:
The following subsections explain the explanation according to the particular circumstance.
Explanation:
- The boiling point seems to be the temperature beyond which the working fluid as well as the boiling phase would be at a predetermined pressure or voltage at equilibrium among one another and.
- The vapor or boiling temperature of 1,1 difluoroethane seems to be -25oC at 1 atm, although as a gas it can remain at a higher temperature around -24oC.
Answer: A. 4 unpaired electrons
B. Zero unpaired electrons
C. 1 unpaired electron
D. 5 unpaired electrons
E. Zero unpaired electrons
Explanation:
In A, Oxidation state of Co is +3 and Electronic configuration is [Ar]3d6
F is weak field ligand, causes no pairing of Electrons hence it has 4 unpaired electrons&2 are paired in t2g orbitals (dXY)
In B , Mn is in +3 with electronic configuration 3d4&CN is a strong field ligand hence causes pairing of Electrons hence it results 0 unpaired electron
In C, Mn is in +2 with electronic configuration 3d5 sinceCN is a strong field ligand hence it leaves one unpaired electron
In D, Mn is in+2 with 3d5& five unpaired electrons since cl is a weak field ligand causes no pairing.
In E, Rh is in +3, with d6 configuration and it is a low spin complex hence pairing of Electrons involved. So it leaves zero unpaired electrons.
Mixture. Mixtures can be both heterogeneous and homogeneous. Heterogeneous mixtures are mixtures that don't have a fixed composition, meaning that if you take smaller samples from two different parts of a larger sample, the ratios of the substances will differ.
