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umka2103 [35]
2 years ago
9

A cart weighing 13kg is pushed by a vendor. If the cart accelerates at 3.5 m/s2

Chemistry
1 answer:
klemol [59]2 years ago
3 0

Answer:

If the cart accelerates at 3.5m/s2, what is the net external force exerted by the vendor? Given: Solution: m= 13kg F=ma a= 3.5m/s2 =13kg x 3.5m/s2 Find: =45.5kg*m/s2 or 45.5 N Fnet The net force exerted by the vendor was 45.5N. 4. 2.

Explanation:

please mark me as the brainliest answer and please follow me for more answers to your questions.

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Predict what will observe in below mention experiment.
Sloan [31]

Predict what will be observed in each experiment below. Rock candy is formed when excess sugar is dissolved in hot water followed by crystallization. A student wants to make two batches of rock candy. He finds an unopened box of "cane sugar" in the pantry. He starts preparing batch A by dissolving sugar in 500 mL of hot water (70 degree C). He keeps adding sugar until no more sugar dissolves in the hot water. He cools the solution to room temperature. He prepares batch B by dissolving sugar in 500 mL of water at room temperature until no more sugar is dissolved. He lets the solution sit at room temperature

a. It is likely that more rock candy will be formed in batch A.

b. It is likely that less rock candy will be formed in batch A.

c. It is likely that no rock candy will be formed in either batch.

d. I need more information to predict which batch is more likely to form rock candy.

Answer: Option A

Explanation:

More rock candy will be formed in the batch A because it is dissolved in hot water and less rock candy will be formed in batch B because the water is not hot.

Formation of the candies require hot water as the solubility of sugar is more in hot water as compared to normal water.

The sugar will be dissolved in water until the time all the space is filled sugar molecules.

Hence, the correct answer is Option A.

6 0
2 years ago
Select the correct set of quantum numbers (n, l, ml, ms) for the first electron removed in the formation of a cation for stronti
matrenka [14]

Answer:

5,0,0,-1/2

Explanation:

The quantum numbers are a way to characterize the electrons, and so, identify the region that it's more probable to find it (orbital). They are:

- Principal quantum number (n): represents the shell or level, and varies from 1 to 7, and are represented by the letter K, L, M, N, O, P, and Q.

- Azimuthal quantum number (l): represents the subshell or sublevel, and is represented by 0,1,2,3.., and for the letters s, p, d, f,...

- Magnetic quantum number (ml): represents the orbital. It varies from -l to +l passing by 0. Each orbital can have 2 electrons.

- Spin quantum number (ms): represents the spin of the electron. It can be +1/2 or -1/2.

The strontium has an atomic number equal to 38, by the Linus Pauling's diagram, the electronic distribution is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²

The valence electron is at the subshell 5s, which has only one magnetic quantum number: 0. Because it has 2 electrons, the first one has spin =1/2, and the other -1/2. So the first electron of the formation of cation has quantum numbers:

n = 5; l = 0; ml = 0; ms = -1/2

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S, sulfur does not have a noble gas electron.
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