Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Answer:
177 $
Step-by-step explanation:
20 x8 = 160
3x3= 9
4x2=8
8+9+160= 177
The equation correctly modeled would be
1000+.02t = 15000
What we know:
quotient 9.2 x 10^6/ 2.3 x 10²
in quotients exponents are subtracted of they have the same base, for example 10^6 and 10² have the same base of 10
What we need to find: quotient 9.2 x 10^6/ 2.3 x 10²
9.2 x 10^6
-------------- = 4 x 10^4
2.3 x 10²
Here in this problem I divided 9.2 by 2.3 and got 4, since the solution was simple and clean meaning no repeated decimals I went ahead and divided the 10^6 by 10^2 and got 10^4.
Another method would be to expand both numbers then divide and do scientific notation again.
Remember to change to normal notation you move the decimal to the right using the number of the exponent.
9.2 x 10^6= 9200000
2.3 x 10²= 230
920000/230=40000
40000= 4 x 10^4 scientific notation
Use the method that is best for you or just know you can use either method to check your work.
It is approximately 1.000
