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GaryK [48]
2 years ago
5

7 days left until launch of products with $668 left in budget. Need to spend $85 on last day. How many dollars do we spend on re

maining days?
Mathematics
1 answer:
Sidana [21]2 years ago
8 0

Answer:

In total, you have $668.00.

To reserve enough for the last day, you need to subtract the last day's budget:

This means that, for the remaining 6 days in the week, you have $583.00.

Assuming an equal amount is being spent each day, you can calculate the daily budget by dividing the remaining total by the number of days left.

To avoid going over budget, you can spend $97.16 per day for the other six days.

Hope this helps!

Step-by-step explanation:

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What is the quotient of 5472 and 81?
Akimi4 [234]

Answer:

67

Step-by-step explanation:

Division:-

\sf\Large\qquad\quad67\\ \begin{array}{cc} \cline{2 - 2}\sf 81 )&\sf \ 5472\\&\sf -487 \downarrow\\ \cline{2-2}& \sf \ \ \ \ 602\\ &\sf \ - 567 \\ \cline{2-2} & \sf \ \035 \\ \cline{2-2} \end{array}\\\\\\ Divisor \rightarrow 81 \\ \\ Quotient \rightarrow 67\\\\Remainder \rightarrow 35

5 0
1 year ago
Freshmen and Sophomores Solve by setting up a system of linear equations with 2 variables and 2 unknowns. A total of 1,595 first
VMariaS [17]

Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595   (1)
s + 15 = r      (2)

Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595  Combine like terms
2s + 15 = 1595      Subtract 15 from both sides
2s = 1595 - 15    
2s = 1580              Divide by 2
s = 1580/2
s = 795 sophmores.

s + r = 1595
795 + r = 1595     Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen

Answer C <<<<<<
8 0
2 years ago
Read 2 more answers
Expand (3 - 2x)6. What is the coefficient of the sixth term?
stich3 [128]
To expand (3 - 2x)^6 use the binomial theorem:

(x + y)^ n = C(n,0) x^ny^0 + C(n,1)x^(n-1) y + C(n,2)x^(n-2) y^2 + ...+ C(n,n+1)xy^(n-1) + C(n,n)x^0y^n


So, for x = 3, y = -2x , and n = 6 you get:

(3 - 2x) ^6 = C(6,0)(3)^6 + C(6,1)(3)^5 (-2x) + C(6,2) (3)^4 (-2x)^3 + C(6,3) (3^3) (-2x)^4 + C(6,4)(3)^2 (-2x)^4 + C(6,5) (3) (-2x)^5 + C(6,6) (-2x)^6

So, the sixth term is C(6,5)(3)(-2x)^5 =  6! / [5! (6-5)! ] * 3 * (-2)^5 x^5 = - 6*3*32 = - 576 x^5.

The coefficient of that term is - 576.

Answer: - 576
5 0
2 years ago
A pattern is made from four congruent squares
exis [7]

Answer:

more information please

Step-by-step explanation:

3 0
2 years ago
Which is the smallest 0.37 0.194 0.6 0.473 0.29
wolverine [178]

0.37

0.194

0.6

0.473

0.29

the smallest digit at tenth place is 1 in 0.194, so 0.194 is the smallest here

4 0
2 years ago
Read 2 more answers
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