Two common forms of phosphorus are red and white. Red phosphorus is fairly stable at room temperature in air, but white phosphor
1 answer:
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Complete Question
Question 096 Propose a three-step synthetic sequence to accomplish the transformation below.
Option 1 => 1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2CCNa
Option 2 => 1) NaOEt; 2) HBr, ROOR; 3) CH3CH2CCNa
Option 3 => 1) t-BuOK; 2) NaNH2; 3) CH3CH2CCNa
Option 4 => 1) CH3CH2CH2CH2Br; 2) NaOEt; 3) HBr, ROOR
Option 5 => 1) t-BuOK; 2) HBr, ROOR; 3) CH3CH2CCNa
Option 6 => 1) NaOEt; 2) NBS, hν; 3) NaSBu
Answer:
The correct option is option 5
Explanation:
The mechanism of the reaction is shown on the first uploaded image
Answer:
1.82 g is the maximum mass of CuS.
Explanation:
Considering:
Or,
Given :
<u>For :
</u>
Molarity = 0.500 M
Volume = 38.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 38.0×10⁻³ L
Thus, moles of :
<u>Moles of = 0.019 moles
</u>
<u>For :
</u>
Molarity = 0.600 M
Volume = 42.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 42.0×10⁻³ L
Thus, moles of :
<u>Moles of = 0.0252 moles
</u>
According to the given reaction:
1 mole of reacts with 1 mole of
So,
0.019 mole of reacts with 0.019 mole of
Moles of = 0.019 mole
Available moles of = 0.0252 mole
<u>Limiting reagent is the one which is present in small amount. Thus, is limiting reagent.</u>
The formation of the product is governed by the limiting reagent. So,
1 mole of gives 1 mole of
0.019 mole of gives 0.019 mole of
Moles of formed = 0.019 moles
Molar mass of = 95.611 g/mol
Mass of = Moles × Molar mass = 0.019 × 95.611 g = 1.82 g
<u>1.82 g is the maximum mass of CuS.</u>